Oxidation state of potassium in K_2_O, K_2O_2 & KO_2 are respectively

Options

A. `+1, +1, +1`
B. `+1, +2, +4`
C. `+1, +2, +2`
D. `+1, +4, +2`

Answer

To find the oxidation state of potassium in the compounds K₂O, K₂O₂, and KO₂, we can follow these steps:

### Step 1: Determine the oxidation state in K₂O
1. **Write the formula**: K₂O
2. **Assign oxidation states**: Let the oxidation state of potassium (K) be \( x \). The oxidation state of oxygen (O) in oxides is typically -2.
3. **Set up the equation**: Since there are 2 potassium atoms, the equation can be written as:
\[ 2x + (-2) = 0 \]
4. **Solve for \( x \)**:
\[ 2x - 2 = 0 \implies 2x = 2 \implies x = +1 \]
5. **Conclusion**: The oxidation state of potassium in K₂O is +1.

### Step 2: Determine the oxidation state in K₂O₂
1. **Write the formula**: K₂O₂
2. **Assign oxidation states**: Let the oxidation state of potassium (K) be \( x \). The oxidation state of oxygen in peroxides is -1.
3. **Set up the equation**: The equation can be written as:
\[ 2x + 2(-1) = 0 \]
4. **Solve for \( x \)**:
\[ 2x - 2 = 0 \implies 2x = 2 \implies x = +1 \]
5. **Conclusion**: The oxidation state of potassium in K₂O₂ is +1.

### Step 3: Determine the oxidation state in KO₂
1. **Write the formula**: KO₂
2. **Assign oxidation states**: Let the oxidation state of potassium (K) be \( x \). The oxidation state of oxygen in superoxides is -1/2.
3. **Set up the equation**: The equation can be written as:
\[ x + 2(-\frac{1}{2}) = 0 \]
4. **Solve for \( x \)**:
\[ x - 1 = 0 \implies x = +1 \]
5. **Conclusion**: The oxidation state of potassium in KO₂ is +1.

### Final Answer
The oxidation states of potassium in K₂O, K₂O₂, and KO₂ are respectively:
- K₂O: +1
- K₂O₂: +1
- KO₂: +1

### Summary of Results
- K₂O: +1
- K₂O₂: +1
- KO₂: +1