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Decreasing order of dipole moment in CHC...

Decreasing order of dipole moment in CHCl3, CCl4 & CH4 is –

A

`CH Cl _ 3 gt C Cl _ 4 = CH _ 4 `

B

` CHCl _ 3 gt C Cl _ 4 gt CH _ 4 `

C

` C Cl _ 4 gt CHCl _ 3 gt CH _ 4 `

D

`C Cl _ 4 = CH _ 4 gt CH Cl _ 3 `

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To determine the decreasing order of dipole moments in CHCl3 (chloroform), CCl4 (carbon tetrachloride), and CH4 (methane), we can analyze the molecular structures and their symmetry. ### Step-by-Step Solution: 1. **Identify the Molecular Structures**: - **CHCl3 (Chloroform)**: This molecule has one hydrogen atom and three chlorine atoms bonded to a central carbon atom. The structure is tetrahedral. - **CCl4 (Carbon Tetrachloride)**: This molecule has four chlorine atoms bonded to a central carbon atom, also forming a tetrahedral structure. - **CH4 (Methane)**: This molecule has four hydrogen atoms bonded to a central carbon atom, forming a tetrahedral structure. 2. **Determine Hybridization**: - All three molecules (CHCl3, CCl4, and CH4) have a carbon atom that is sp³ hybridized, leading to a tetrahedral geometry. 3. **Analyze Symmetry**: - **CCl4**: The molecule is symmetrical because all four substituents (Cl) are identical. The dipole moments from each C-Cl bond cancel each other out, resulting in a net dipole moment of **0**. - **CH4**: Similar to CCl4, methane is symmetrical with four identical hydrogen atoms. The dipole moments from each C-H bond also cancel out, resulting in a net dipole moment of **0**. - **CHCl3**: This molecule is not symmetrical due to the presence of one hydrogen atom and three chlorine atoms. The dipole moments from the C-Cl bonds do not cancel out with the C-H bond, leading to a net dipole moment that is greater than **0**. 4. **Compare the Dipole Moments**: - Since both CCl4 and CH4 have a dipole moment of **0**, while CHCl3 has a positive dipole moment, we can conclude: - **Dipole Moment of CHCl3 > Dipole Moment of CCl4 = Dipole Moment of CH4 = 0**. 5. **Final Order**: - The decreasing order of dipole moments is: - **CHCl3 > CCl4 = CH4**. ### Conclusion: The decreasing order of dipole moment in CHCl3, CCl4, and CH4 is: **CHCl3 > CCl4 = CH4**.
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