NaOH (Hot + Conc.) + `Cl_2` rarr A + other products and `Ca(OH)_2`(Cold and dilute) + `Cl_2` rarr B + other products . A and B are respectively:

Options

A. `NaClO_3, Ca(OCl)_2`
B. `NaClO_3, Ca(ClO_3)_2`
C. `NaCl, Ca(ClO_3)_2`
D. `NaClO, Ca(ClO_3)_2`

Answer

To solve the question, we need to analyze the reactions of hot concentrated sodium hydroxide (NaOH) with chlorine (Cl₂) and cold dilute calcium hydroxide (Ca(OH)₂) with chlorine (Cl₂).

### Step 1: Reaction of Hot Concentrated NaOH with Cl₂
When hot concentrated NaOH reacts with chlorine, the main products formed are sodium chloride (NaCl) and sodium chlorate (NaClO₃). The balanced chemical equation for this reaction can be represented as follows:

\[ 6 \text{NaOH} + 3 \text{Cl}_2 \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2\text{O} \]

From this reaction, we can identify:
- **Product A**: NaClO₃

### Step 2: Reaction of Cold Dilute Ca(OH)₂ with Cl₂
Next, we consider the reaction of cold dilute calcium hydroxide with chlorine. In this case, the products formed are calcium chloride (CaCl₂) and calcium oxychloride (Ca(OCl)₂). The balanced chemical equation for this reaction is:

\[ 2 \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow 2 \text{CaCl}_2 + \text{Ca(OCl)}_2 + 2 \text{H}_2\text{O} \]

From this reaction, we can identify:
- **Product B**: Ca(OCl)₂

### Final Answer
Thus, the products A and B are:
- **A**: NaClO₃
- **B**: Ca(OCl)₂