There are two beakers (I) having pure volatile solvent and (II) having volatile solvent and non-volatile solute. If both beakers are placed together in a closed container then:

Options

A. Volume of solvent beaker will decrease and solution beaker will increase
B. Volume of solvent beaker will increase and solution beaker will also increase
C. Volume of solvent beaker will decrease and solution beaker will also decrease
D. Volume of solvent beaker will increase and solution beaker will decrease

Answer

To solve the problem, we need to analyze the situation involving two beakers: one containing pure volatile solvent and the other containing a volatile solvent mixed with a non-volatile solute. Both beakers are placed in a closed container.

### Step-by-Step Solution:

1. **Identify the Components**:
- Beaker I contains pure volatile solvent.
- Beaker II contains a solution of volatile solvent and a non-volatile solute.

2. **Understand Vapor Pressure**:
- The vapor pressure of the pure solvent (Beaker I) is denoted as \( P_0 \).
- The vapor pressure of the solution (Beaker II) is denoted as \( P_s \).
- According to colligative properties, the addition of a non-volatile solute lowers the vapor pressure of the solvent. Therefore, \( P_0 > P_s \).

3. **Behavior in a Closed Container**:
- Since the container is closed, the system will reach equilibrium. The solvent from Beaker I will tend to evaporate into the vapor phase because it has a higher vapor pressure compared to the solution in Beaker II.

4. **Vaporization Process**:
- The solvent from Beaker I will vaporize and move towards Beaker II, where the vapor pressure is lower. This process continues until equilibrium is reached.

5. **Volume Changes**:
- As the solvent evaporates from Beaker I, its volume will decrease.
- Conversely, as the vapor condenses in Beaker II, the volume of the solution will increase.

6. **Equilibrium State**:
- At equilibrium, both beakers will have the same vapor pressure, but Beaker II will have a higher volume due to the added solvent.

7. **Conclusion**:
- The volume of Beaker I (pure solvent) will decrease.
- The volume of Beaker II (solution) will increase.

### Final Answer:
- The volume of the solvent beaker (Beaker I) will decrease, and the volume of the solution beaker (Beaker II) will increase.