Which of the following complex exhibit facial meridional geometrical isomerism.

Options

A. `[Pt(NH_(3))Cl_(3)]^-`
B. `[PtCl_(2)(NH_(3))_(2)]`
C. `[Ni(CO)_(4)]`
D. `[Co(NO_(2))_3 (NH_(3))_(3)]`

Explanation

To determine which of the following complexes exhibit facial and meridional geometrical isomerism, we need to analyze the coordination number and the arrangement of ligands in the complexes provided.

### Step-by-Step Solution:

1. **Understanding Geometrical Isomerism**:
- Geometrical isomerism in coordination compounds can occur in octahedral complexes (coordination number 6) with the general formula \( MA_3B_3 \), where \( A \) and \( B \) are different ligands.
- In these complexes, we can have two types of isomers:
- **Facial (FAC)**: where the same type of ligands occupy adjacent positions.
- **Meridional (MER)**: where the same type of ligands occupy positions that form a plane through the metal center.

2. **Identifying the Coordination Number**:
- We need to check the coordination number of each complex given in the options. Only complexes with a coordination number of 6 can exhibit facial and meridional isomerism.

3. **Analyzing Each Option**:
- **Option A**: Platinum complex with 4 ligands (3 Cl and 1 NH3).
- Coordination number = 4.
- **Conclusion**: Does not exhibit facial/meridional isomerism.

- **Option B**: Another platinum complex with 4 ligands (2 Cl and 2 NH3).
- Coordination number = 4.
- **Conclusion**: Does not exhibit facial/meridional isomerism.

- **Option C**: Nickel complex \( Ni(CO)_4 \).
- Coordination number = 4.
- **Conclusion**: Does not exhibit facial/meridional isomerism.

- **Option D**: Cobalt complex with 6 ligands (3 NH3 and 3 NO2).
- Coordination number = 6 (A3B3 type).
- **Conclusion**: Exhibits both facial and meridional isomerism.

4. **Final Answer**:
- The only complex that exhibits facial and meridional geometrical isomerism is **Option D**.

### Summary:
- **Correct Option**: D (Cobalt complex with 3 NH3 and 3 NO2 ligands).