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Differential equation of x^2= 4b(y + b),...

Differential equation of `x^2= 4b(y + b)`, where b is a parameter, is

A

`x((dy)/(dx))^2=2y((dy)/(dx))+x^2`

B

`x((dy)/(dx))^2=2y((dy)/(dx))+x`

C

`x((dy)/(dx))^2=y((dy)/(dx))+x^2`

D

`x((dy)/(dx))^2=2y((dy)/(dx))+2x^2`

Text Solution

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The correct Answer is:
To find the differential equation of the given equation \( x^2 = 4b(y + b) \), where \( b \) is a parameter, we can follow these steps: ### Step 1: Differentiate the given equation with respect to \( x \) We start with the equation: \[ x^2 = 4b(y + b) \] Differentiating both sides with respect to \( x \): \[ \frac{d}{dx}(x^2) = \frac{d}{dx}(4b(y + b)) \] Using the chain rule on the right side, we have: \[ 2x = 4b\left(\frac{dy}{dx}\right) \] ### Step 2: Solve for \( b \) From the differentiated equation, we can express \( b \): \[ b = \frac{2x}{4\frac{dy}{dx}} = \frac{x}{2\frac{dy}{dx}} \] ### Step 3: Substitute \( b \) back into the original equation Now we substitute \( b \) back into the original equation: \[ x^2 = 4\left(\frac{x}{2\frac{dy}{dx}}\right)(y + \frac{x}{2\frac{dy}{dx}}) \] ### Step 4: Simplify the equation This simplifies to: \[ x^2 = 2x\left(y + \frac{x}{2\frac{dy}{dx}}\right) \] Distributing the right side: \[ x^2 = 2xy + \frac{x^2}{\frac{dy}{dx}} \] ### Step 5: Rearranging the equation Rearranging gives: \[ x^2 - 2xy = \frac{x^2}{\frac{dy}{dx}} \] ### Step 6: Multiply through by \( \frac{dy}{dx} \) Multiplying through by \( \frac{dy}{dx} \) gives: \[ x^2 \frac{dy}{dx} - 2xy \frac{dy}{dx} = x^2 \] ### Step 7: Rearranging to form the differential equation Rearranging this gives us: \[ x^2 \frac{dy}{dx} = 2xy \frac{dy}{dx} + x^2 \] ### Step 8: Final form of the differential equation Thus, we can express the differential equation as: \[ x \left(\frac{dy}{dx}\right)^2 = 2y \frac{dy}{dx} + x \] This can be rewritten as: \[ x \left(\frac{dy}{dx}\right)^2 - 2y \frac{dy}{dx} - x = 0 \] ### Final Answer: The differential equation is: \[ x \left(\frac{dy}{dx}\right)^2 = 2y \frac{dy}{dx} + x \] ---

To find the differential equation of the given equation \( x^2 = 4b(y + b) \), where \( b \) is a parameter, we can follow these steps: ### Step 1: Differentiate the given equation with respect to \( x \) We start with the equation: \[ x^2 = 4b(y + b) \] ...
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