Which of the following exhibit both Frenkel & Schottky defect?

Options

A. AgBr
B. KCl
C. CsCl
D. ZnS

Explanation

To determine which compound exhibits both Frenkel and Schottky defects, we need to understand the characteristics of these defects and analyze the given options.

### Step-by-Step Solution:

1. **Understanding Frenkel Defect**:
- A Frenkel defect occurs when a cation leaves its normal lattice site and occupies an interstitial site. This defect typically arises in ionic compounds where there is a significant size difference between cations and anions.

2. **Understanding Schottky Defect**:
- A Schottky defect occurs when equal numbers of cations and anions are missing from the lattice, creating vacancies. This defect is common in ionic solids where the cation and anion are of similar size.

3. **Identifying Compounds**:
- We need to analyze the provided options:
- **Option A: AgBr**
- **Option B: KCl**
- **Option C: CsCl**
- **Option D: ZnS**

4. **Analyzing Each Option**:
- **AgBr**:
- AgBr can exhibit both Frenkel and Schottky defects. The silver ion (Ag⁺) can move to an interstitial site (Frenkel defect), and both Ag⁺ and Br⁻ can be missing from their lattice sites (Schottky defect).
- **KCl**:
- KCl typically exhibits only Schottky defects due to the similar size of K⁺ and Cl⁻ ions.
- **CsCl**:
- CsCl also primarily exhibits Schottky defects, as the cation and anion are of similar size.
- **ZnS**:
- ZnS generally shows Frenkel defects but does not exhibit Schottky defects.

5. **Conclusion**:
- Among the options, **AgBr** is the only compound that exhibits both Frenkel and Schottky defects.

### Final Answer:
**Option A: AgBr** is the correct answer.