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There are two compounds A and B of molec...

There are two compounds A and B of molecular formula `C_(9)H_(18)O_(3)`. A has higher boiling point than B. What are the possible structures of A and B?

A

B

C

D

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To determine the possible structures of compounds A and B with the molecular formula \( C_9H_{18}O_3 \) where compound A has a higher boiling point than compound B, we can analyze the structures based on the presence of functional groups and their ability to form hydrogen bonds. ### Step 1: Identify the Functional Groups - The molecular formula \( C_9H_{18}O_3 \) suggests that both compounds could contain alcohol (-OH) groups and ether (R-O-R') groups. - Alcohols can form hydrogen bonds, which typically lead to higher boiling points compared to ethers, which cannot form hydrogen bonds as effectively. ### Step 2: Analyze the Boiling Point - Since compound A has a higher boiling point than compound B, we can infer that A likely contains more alcohol groups than B. This is because the presence of more hydroxyl (-OH) groups increases the potential for hydrogen bonding, leading to a higher boiling point. ### Step 3: Propose Possible Structures - **Compound A**: To have a higher boiling point, we can propose that compound A has three hydroxyl groups (making it a triol). A possible structure could be: - Structure of A: - 1,2,3-Propanetriol (Glycerol) with additional carbon chains to fulfill the molecular formula. - **Compound B**: In contrast, compound B can be an ether with fewer hydroxyl groups. A possible structure could be: - Structure of B: - A tri-ether structure, where three ether groups are present, leading to lower hydrogen bonding capability. ### Step 4: Validate the Structures - We can validate that the proposed structures fit the molecular formula \( C_9H_{18}O_3 \): - For compound A (triol), we can have: - \( C_3H_8O_3 \) (Glycerol) plus additional carbons to reach \( C_9 \). - For compound B (tri-ether), we can have: - \( C_9H_{18}O_3 \) structured as three ether groups. ### Conclusion - Therefore, the possible structures are: - **Compound A**: A triol with three -OH groups. - **Compound B**: A tri-ether with no -OH groups. ### Summary of Structures - **A**: Triol (e.g., 1,2,3-propanetriol with additional carbon chains) - **B**: Tri-ether (e.g., three ether groups)

To determine the possible structures of compounds A and B with the molecular formula \( C_9H_{18}O_3 \) where compound A has a higher boiling point than compound B, we can analyze the structures based on the presence of functional groups and their ability to form hydrogen bonds. ### Step 1: Identify the Functional Groups - The molecular formula \( C_9H_{18}O_3 \) suggests that both compounds could contain alcohol (-OH) groups and ether (R-O-R') groups. - Alcohols can form hydrogen bonds, which typically lead to higher boiling points compared to ethers, which cannot form hydrogen bonds as effectively. ### Step 2: Analyze the Boiling Point - Since compound A has a higher boiling point than compound B, we can infer that A likely contains more alcohol groups than B. This is because the presence of more hydroxyl (-OH) groups increases the potential for hydrogen bonding, leading to a higher boiling point. ...
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