Complex `[ML_(5)]` can exhibit trigonal bipyramidal and square pyramidal geometry. Determine total number of `180^@, 90^@ & 120^@` L-M-L bond angles.
Complex `[ML_(5)]` can exhibit trigonal bipyramidal and square pyramidal geometry. Determine total number of `180^@, 90^@ & 120^@` L-M-L bond angles.
A
(a) 14
B
(b) 20
C
(c) 10
D
(d) 25
Text Solution
AI Generated Solution
The correct Answer is:
To determine the total number of 180°, 90°, and 120° L-M-L bond angles in the complex [ML₅] that exhibits trigonal bipyramidal (TBP) and square pyramidal geometries, we will analyze each geometry step by step.
### Step 1: Analyze Trigonal Bipyramidal Geometry
In trigonal bipyramidal geometry, the arrangement of ligands around the central metal atom is such that there are two axial positions and three equatorial positions.
1. **180° Angles**:
- There is only **1 angle** of 180° between the two axial ligands (L1 and L3).
2. **90° Angles**:
- Each equatorial ligand (L2, L4, L5) forms a 90° angle with the axial ligands (L1 and L3).
- There are **6 angles** of 90° (3 angles with L1 and 3 angles with L3).
3. **120° Angles**:
- The equatorial ligands (L2, L4, L5) form 120° angles with each other.
- There are **3 angles** of 120° (L2-L4, L2-L5, and L4-L5).
**Total for TBP**:
- 180°: 1
- 90°: 6
- 120°: 3
### Step 2: Analyze Square Pyramidal Geometry
In square pyramidal geometry, there are four ligands in a square plane and one ligand above the plane.
1. **180° Angles**:
- There are **2 angles** of 180° (between L2 and L4, and L3 and L5).
2. **90° Angles**:
- The ligand above the plane (L1) forms 90° angles with all four ligands in the square plane (L2, L3, L4, L5).
- Additionally, the ligands in the square plane also form 90° angles with each other.
- There are **8 angles** of 90° (4 with L1 and 4 between the ligands in the square plane).
3. **120° Angles**:
- There are **0 angles** of 120° in square pyramidal geometry.
**Total for Square Pyramidal**:
- 180°: 2
- 90°: 8
- 120°: 0
### Step 3: Combine Results
Now, we will combine the results from both geometries:
- **Total 180° Angles**: 1 (TBP) + 2 (Square Pyramidal) = 3
- **Total 90° Angles**: 6 (TBP) + 8 (Square Pyramidal) = 14
- **Total 120° Angles**: 3 (TBP) + 0 (Square Pyramidal) = 3
### Final Count of Bond Angles
- **Total 180° angles**: 3
- **Total 90° angles**: 14
- **Total 120° angles**: 3
### Total Number of L-M-L Bond Angles
Adding all the bond angles together:
- Total = 3 (180°) + 14 (90°) + 3 (120°) = **20**
### Conclusion
The total number of L-M-L bond angles in the complex [ML₅] is **20**.
To determine the total number of 180°, 90°, and 120° L-M-L bond angles in the complex [ML₅] that exhibits trigonal bipyramidal (TBP) and square pyramidal geometries, we will analyze each geometry step by step.
### Step 1: Analyze Trigonal Bipyramidal Geometry
In trigonal bipyramidal geometry, the arrangement of ligands around the central metal atom is such that there are two axial positions and three equatorial positions.
1. **180° Angles**:
- There is only **1 angle** of 180° between the two axial ligands (L1 and L3).
...
|
Similar Questions
Explore conceptually related problems
In a regular trigonal bipyramidal MX_(5) , the number of X - M - X bonds at 180^(@) is
Watch solution
Among the following statements:- I. PCl_(5) is trigonal bipyramidal wheras IF_(5) is square pyramidal. II. Bond enthalpy of O-H bond in water and ethanol is different. III. All carbon atoms have same hybridisation in carbon suboxide (C_(3)O_(2)) Find out the correct statements.
Watch solution
A coordination complex of type MX_(2)Y_(2) (M-metal ion: X, Y-monodentate lingads), can have either a tetrahedral or a square planar geometry. The maximum number of posible isomers in these two cases are respectively:
Watch solution
A coordination complex of type MX_(2)Y_(2) (M-metal ion: X, Y-monodentate lingads), can have either a tetrahedral or a square planar geometry. The maximum number of posible isomers in these two cases are respectively:
Watch solution
Consider the following covalent compounds in their solid state and find the value of expression (X+Y+Z) . N_(2)O_(5),Cl_(2)O_(6),PC l_(),I_(2)Cl_(6),XeF_(6),PB r_(5) Where X=total number of compounds in which central atom of cationic or anionic part is sp^(3) hybridized. Y=Total number of compounds having 90^(@) bond angle either in cationic or anionic part. Z=Total number of compounds having 109^(@)28' bond angle either in cationic or anionic part.
Watch solution
ICI_3 is an orange colored solid that dimerizes in solid state as I_2Cl_6 Based on VSEPR theory , number of 90 degree Cl-l-Cl bond angles is …….. In the dimeric species.
Watch solution
The concept of hybridisation has been introduced to explain the shapes of molecules. It involves the intermixing of two or more atomic orbitals belonging to same atom but in or more atomic orbitals belonging to same atom but in different sub-shells so as to intermix and redistribute energies to from equivalent orbitals called hybrid orbitals. Depending upon total number and nature of the orbitals involved, the hybridisation may be divided into sp (linear), sp^(2) (trigonal), sp^(3) (tetrahedral), sp^(3)d (trigonal bipyramidal), sp^(3)d^(3) (octahedral) and sp^(3)d^(3) (pentagonal bipyramidal) types. it may be noted that the orbitals of isolated atoms never hybridize and they do so at the time of bond formation. A hybrid orbital from s-and p-orbitals can contribute to
Watch solution
Consider the following compounds (1) H_(3)CF (2) H_(2)CF_(2) (3) CH_(4) (4) H_(3)C CF_(3) (5) CH_(3)CH_(2)+ (6) C_(2)H_(4) and calculate value of Y+X, (where X is the total number of compounds which have H-C-H bond angles equal to 109^(@)28' and Y is the total number of compounds which have H-C-H bond angles greater than 109^(@)28' and less than 120^(@)
Watch solution
Consider the following compounds (1) H_(3)CF (2) H_(2)CF_(2) (3) CH_(4) (4) H_(3)C CF_(3) (5) CH_(3)CH_(3) (6) C_(2)H_(4) and calculate value of Y+X, (where X is the total number of compounds which have H-C-H bond angles equal to 109^(@)28' and Y is the total number of compounds which have H-C-H bond angles greater than 109^(@)28' and less than 120^(@)
Watch solution
Total number of F-l-F bond angles which are 90^(@) present in lF_(7) is
Watch solution
Recommended Questions
- Complex [ML(5)] can exhibit trigonal bipyramidal and square pyramidal ...
05:49
|
Playing Now - Which of the molecules has trigonal bipyramidal geometry with bond ang...
02:04
|
Play - Explain why PCl(5) is trigonal bipyramidal whereas IF(5) is square pyr...
01:42
|
Play - The trigonal bipyramidal geometry results from the hybridisation
01:47
|
Play - Explain why PCl(5) is trigonal bipyramidal whereas IF(5) is square pyr...
01:42
|
Play - Complex [ML(5)] can exhibit trigonal bipyramidal and square pyramidal ...
04:53
|
Play - For the complex ML(2) stepwise formation constants for M+L hArr ML...
02:49
|
Play - In a regular trigonal bipyramidal MX(5) , the number of X - M - X bond...
01:57
|
Play - In the geometry of a complex compound, the molecule is trigonal bipyra...
Text Solution
|
Play