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A telescope of aperture diameter 5m is used to observe the moon from the earth. Distance between the moon and earth is `4 xx 10^5` km. Determine the minimum distance between two points on the moon's surface which can be resolved using this telescope. (Wave length of light is `5893 A^@`.

A

60m

B

20 m

C

600 m

D

200 m

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The correct Answer is:
To determine the minimum distance between two points on the moon's surface that can be resolved using a telescope, we can use the formula for angular resolution given by Rayleigh's criterion: \[ \theta = \frac{1.22 \lambda}{D} \] Where: - \(\theta\) is the angular resolution in radians, - \(\lambda\) is the wavelength of light, - \(D\) is the diameter of the telescope's aperture. ### Step 1: Convert the given values to appropriate units - The wavelength \(\lambda = 5893 \, \text{Å} = 5893 \times 10^{-10} \, \text{m}\) - The diameter of the telescope's aperture \(D = 5 \, \text{m}\) - The distance from the Earth to the Moon \(r = 4 \times 10^5 \, \text{km} = 4 \times 10^8 \, \text{m}\) ### Step 2: Calculate the angular resolution \(\theta\) Using the formula: \[ \theta = \frac{1.22 \lambda}{D} \] Substituting the values: \[ \theta = \frac{1.22 \times 5893 \times 10^{-10}}{5} \] Calculating this gives: \[ \theta \approx \frac{1.22 \times 5893 \times 10^{-10}}{5} \approx 1.44 \times 10^{-13} \, \text{radians} \] ### Step 3: Calculate the minimum resolvable distance on the moon's surface The minimum distance \(d\) between two points on the moon's surface that can be resolved is given by: \[ d = r \cdot \theta \] Substituting the values: \[ d = (4 \times 10^8) \cdot (1.44 \times 10^{-13}) \] Calculating this gives: \[ d \approx 57.6 \, \text{m} \] ### Step 4: Round to the nearest option Since the closest option to our calculated value is 60 m, we can conclude that: \[ \text{Minimum distance between two points on the moon's surface} \approx 60 \, \text{m} \] ### Final Answer The minimum distance between two points on the moon's surface which can be resolved using this telescope is approximately **60 meters**. ---

To determine the minimum distance between two points on the moon's surface that can be resolved using a telescope, we can use the formula for angular resolution given by Rayleigh's criterion: \[ \theta = \frac{1.22 \lambda}{D} \] Where: - \(\theta\) is the angular resolution in radians, ...
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