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A solution of m - chloroaniline, m- c...

A solution of m - chloroaniline, m- chlorophenol and m - chlorobenzoinc acid in ethyl acetate was extracted initially with a saturated solution of ` Na HCO _ 3 ` to give fraction A. The left over organic phase was extracted with dilute NaOH solution to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C, contain respectively :

A

m - chlorophenol , m - chlorobenzoic acid and m - chloroaniline

B

m - chlorobenzoic acid, m - chloroaniline and m - chlorophenol

C

m - chlorobenzoic acid, m - chlorophenol and m - chloroaniline

D

m - chloroaniline, m - chlorobenzoic acid and m - chlorophenol

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The correct Answer is:
To solve the problem, we need to analyze the extraction process step by step, focusing on the behavior of each compound in the presence of the reagents used. ### Step 1: Identify the Compounds We have three compounds in the solution: 1. m-Chloroaniline (A) 2. m-Chlorophenol (B) 3. m-Chlorobenzoic acid (C) ### Step 2: Extraction with NaHCO3 The first extraction is done using a saturated solution of sodium bicarbonate (NaHCO3), which is a weak base. - **Behavior of the Compounds:** - **m-Chloroaniline (A)**: This is a weak base due to the presence of the amino group (-NH2). It will not react with NaHCO3. - **m-Chlorophenol (B)**: This is a weak acid. It will not react significantly with NaHCO3. - **m-Chlorobenzoic acid (C)**: This is a stronger acid compared to phenol. It will react with NaHCO3 to form a sodium salt (sodium m-chlorobenzoate) and will be extracted into the aqueous phase. **Conclusion for Fraction A**: - Fraction A contains m-Chlorobenzoic acid (C) as it reacts with NaHCO3. ### Step 3: Extraction with Dilute NaOH After the first extraction, we have an organic phase left that contains m-Chloroaniline and m-Chlorophenol. This phase is then extracted with dilute sodium hydroxide (NaOH), which is a strong base. - **Behavior of the Compounds**: - **m-Chloroaniline (A)**: As a weak base, it will remain in the organic phase and will not react with NaOH. - **m-Chlorophenol (B)**: This is a weak acid and will react with NaOH to form sodium m-chlorophenoxide, which will be extracted into the aqueous phase. **Conclusion for Fraction B**: - Fraction B contains m-Chlorophenol (B) as it reacts with NaOH. ### Step 4: Remaining Organic Layer After the extraction with NaOH, the remaining organic layer will contain m-Chloroaniline. **Conclusion for Fraction C**: - Fraction C contains m-Chloroaniline (A) as it does not react with either NaHCO3 or NaOH. ### Final Summary - **Fraction A**: m-Chlorobenzoic acid (C) - **Fraction B**: m-Chlorophenol (B) - **Fraction C**: m-Chloroaniline (A) ### Final Answer - Fraction A contains m-Chlorobenzoic acid, Fraction B contains m-Chlorophenol, and Fraction C contains m-Chloroaniline. ---
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