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The reaction of H(3)N(3)B(3)Cl(3)(A) wit...

The reaction of `H_(3)N_(3)B_(3)Cl_(3)(A)` with `LiBH_(4)` in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads of `H_(3)N_(3)B_(3)(Me)_(3)`. Compounds (B) and (C) respectively , are :

A

Boran nitride and MeBr

B

Diborane and MeMgBr

C

Borazine and MeBr

D

Borazine and MeMgBr

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The correct Answer is:
To solve the given problem, we need to identify the compounds B and C based on the reactions involving compound A, which is \( H_3N_3B_3Cl_3 \). ### Step-by-Step Solution: 1. **Identify Compound A**: - Compound A is \( H_3N_3B_3Cl_3 \). This is a boron-nitrogen compound that contains boron (B) and nitrogen (N) atoms. 2. **Reaction of A with LiBH4**: - When \( H_3N_3B_3Cl_3 \) reacts with lithium borohydride (\( LiBH_4 \)) in tetrahydrofuran (THF), it leads to the formation of an inorganic benzene. - The reaction can be represented as: \[ H_3N_3B_3Cl_3 + LiBH_4 \rightarrow H_3N_3B_3H_3 + LiCl + BH_3 \cdot THF \] - The product \( H_3N_3B_3H_3 \) is known as borazine, which is often referred to as inorganic benzene (B). 3. **Identify Compound B**: - From the above reaction, we conclude that compound B is \( H_3N_3B_3H_3 \) (borazine). 4. **Reaction of A with C**: - The problem states that the reaction of A with another compound C leads to the formation of \( H_3N_3B_3Me_3 \). - To achieve this, compound C must be a methylating agent. A common reagent for methylation in organometallic chemistry is methyl magnesium bromide (\( CH_3MgBr \)). - The reaction can be represented as: \[ H_3N_3B_3Cl_3 + CH_3MgBr \rightarrow H_3N_3B_3Me_3 + MgBrCl \] - This reaction replaces the chlorine atoms in compound A with methyl groups, resulting in \( H_3N_3B_3Me_3 \). 5. **Identify Compound C**: - From the above reaction, we conclude that compound C is \( CH_3MgBr \) (methyl magnesium bromide). ### Final Answer: - Compound B is \( H_3N_3B_3H_3 \) (borazine). - Compound C is \( CH_3MgBr \) (methyl magnesium bromide). ### Summary: - **Compound B**: \( H_3N_3B_3H_3 \) (borazine) - **Compound C**: \( CH_3MgBr \) (methyl magnesium bromide)
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