Lacto bacillus has generation time 60 min. at 300 K and 40 min. at 400 K. Determine activation energy in `(kJ)/(mol)` . (`R = 8.3 J K^ (–1) mol^(–1)` ) `[ log_e (2/3) = - 0.4 ]`

A first order reaction is 50% completed in 30 minutes at 300 K and in 10 minutes at 320 K, Calculate the activation energy of the reaction (R = 8.314 "JK mol"^(-1) .)

A certain reaction is 50% complete in 20 minutes at 300 K and the same reaction is again 50% complete in 5 minutes at 350 K, Calculate the activation energy if it is a first order reaction. [ R = 8.314 JK^(-1) mol^(-1) , log 4 = 0.602 ]

A first order reaction is 50% completed in 40 minutes at 300 K and in 20 minutes at 320 K. Calculate the activation energy of the reaction . (Given : log 2 = 0.3010 , log 4 = 0.6021 , R = 8.314 J K^(-1) mol^(-1) ) .

The rate of a reaction doubles when its temperature changes from 300 K to 310 K . Activation energy of such a reaction will be: (R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

A sample of milk splits after 60 min . At 300 K and after 40 min 400K when the population of lactobacillus acidophilus in it doubles . The activation energy (in KJ/mol) for this process is closest to (Given , R = 8.3 J mol^(-1) K^(-1), " ln" (2/3) = 0.4 , e^(-3) = 4.0)

For a reaction, K = 1.958 xx 10^(-4) at 400 K, what is the value of DeltaG^@ at this temepratuure ? (R = 8.314 J K^(-1) mol^(-1)) .

For a reaction, K_p = 1.8 xx 10^(-7) at 300K. What is the value of DeltaG^@ at this temeprature ? (R =8.314 J K^(-1) mol^(-1))