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When 1 mol CrCl(3) * 6 H(2)O is treate...

When 1 mol `CrCl_(3) * 6 H_(2)O` is treated with excess of `AgNO_(3)` , 3 mol of AgCl are obtained . The formula of the complex is

A

`[Cr(H_2O)_5Cl]Cl_2.H_2O`

B

`[Cr(H_2O)_3Cl_3]3H_2O`

C

`[Cr(H_2O)_4Cl_2]Cl.2H_2O`

D

`[Cr(H_2O)_6]Cl_3`

Text Solution

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The correct Answer is:
d
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