`Cu^(2+) + Sn rarr Sn^(2+) + Cu`
`E^@_cu^(2+)/cu = 0.34, E^@_Sn^(2+)/Sn = -0.16` . find `deltaG^@`

For the given cell arrangement identify incorrect statement given E^@_(Cu^(2+)//Cu) = 0.34V & E^@_(Zn^(2+)//Zn) = -0.76V

The Gibbs energy change (in J) for the given reaction at [Cu^(2+) ] = [Sn^(2+) ] = 1 M and 298 K is : Cu (s) + Sn^(2+) (aq) to Cu^(2+) (aq.) + Sn(s), (E_(Sn^(2+) // Sn)^(0) = -0.16 V E_(Cu^(2+) |Cu)^(0) = 0.34 V , Take F = 96500 C mol^(-1) )

Given : E^(@) (Cu^(2+//Cu) = 0.337V and E^(@) (Sn^(2+//Sn) = -0.136V . Which of the following statements is correct?

E^(@) of Fe^(2 +) //Fe = - 0.44 V, E^(@) of Cu //Cu^(2+) = -0.34 V . Then in the cell

Consider the following E^(@) values E^(@) values E_(Fe^(3+)//Fe^(2+))^(@)= 0.77v , E_(Sn^(2+)//Sn)^(@) = -0.14 under standard condition the potential for the reaction Sn_(s)+ 2Fe^(3+)(aq)rightarrow 2Fe^(2+)(aq) + Sn^(2+) (aq) is :

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

Calculate DeltaG^(@) for the reaction : Cu^(2+)(aq) +Fe(s) hArr Fe^(2+)(aq) +Cu(s) . Given that E^(@)Cu^(2+)//Cu = 0.34 V , E_(Fe^(+2)//Fe)^(@) =- 0.44 V

Calculate the equilibrium constant for the reaction: 3Sn(s) +2Cr_(2)O_(7)^(2-) +28 H^(+) rarr 3Sn^(+4) +4Cr^(3+) +14H_(2)O E^(@) for Sn//Sn^(+2) = 0.136 V E^(@) for4 Sn^(2+)//Sn^(4+) =- 0.154V E^(@) for Cr_(2)O_(7)^(2-)//Cr^(3+) = 1.33V

Find the equilibrium constant of the following reaction Cu^(2+) (aq) +Sn^(2+) (aq) hArr Cu(s) +Sn^(4+) (aq) at 25^(@)C, E_(Cu^(2+)//Cu)^(Theta)=0.34V, E_(Sn^(4+)//Sn^(2+))^(Theta)=0.155V

Calculate the DeltaG^(@) and equilibrium constant of the reaction at 27^(@)C Mg+ Cu^(+2) hArr Mg^(+2) + Cu E_(Mg^(2+)//Mg)^(@) = -2.37V, E_(Cu^(2+)//Cu)^(@) = +0.34V