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If area(A), time(T) and momentum(P) is a...

If area(A), time(T) and momentum(P) is assume as fundamental quantities then dimensional formula of energy will be

A

`AT^(-2)P^1`

B

`A^(1/2)T^(-1)P^2`

C

`A^(1/2)T^(-1)P^1`

D

`AT^(-1/2)P^2`

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The correct Answer is:
To solve the problem of finding the dimensional formula of energy in terms of area (A), time (T), and momentum (P), we will follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: We start with the assumption that energy (E) can be expressed in terms of the fundamental quantities area (A), time (T), and momentum (P). We can write: \[ E \propto A^x T^y P^z \] where \(x\), \(y\), and \(z\) are the powers we need to determine. 2. **Writing the Dimensional Formulas**: - The dimensional formula for area \(A\) is \(L^2\). - The dimensional formula for time \(T\) is \(T^1\). - The dimensional formula for momentum \(P\) is \(MLT^{-1}\). 3. **Expressing Energy's Dimensional Formula**: The dimensional formula of energy in terms of mass (M), length (L), and time (T) is: \[ [E] = ML^2T^{-2} \] 4. **Substituting the Dimensional Formulas**: Substituting the dimensional formulas into our proportionality: \[ [E] = A^x T^y P^z = (L^2)^x (T^1)^y (MLT^{-1})^z \] This expands to: \[ [E] = L^{2x} T^y M^z L^z T^{-z} = M^z L^{2x + z} T^{y - z} \] 5. **Comparing Dimensions**: Now we compare the dimensions of both sides: \[ ML^2T^{-2} = M^z L^{2x + z} T^{y - z} \] This gives us three equations: - For mass (M): \(z = 1\) - For length (L): \(2x + z = 2\) - For time (T): \(y - z = -2\) 6. **Solving the Equations**: From \(z = 1\): - Substitute \(z = 1\) into \(2x + z = 2\): \[ 2x + 1 = 2 \implies 2x = 1 \implies x = \frac{1}{2} \] - Substitute \(z = 1\) into \(y - z = -2\): \[ y - 1 = -2 \implies y = -1 \] 7. **Final Values**: We have determined: - \(x = \frac{1}{2}\) - \(y = -1\) - \(z = 1\) 8. **Writing the Dimensional Formula of Energy**: Therefore, the dimensional formula of energy in terms of area, time, and momentum is: \[ E = A^{\frac{1}{2}} T^{-1} P^1 \] ### Conclusion: The dimensional formula of energy in terms of area (A), time (T), and momentum (P) is: \[ E = A^{\frac{1}{2}} T^{-1} P^1 \]
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