A metal having work function `4.41xx10^(-19) J` is sunjected to a light having wavelength 300nm, then maximum kinetic energy of the emitted photoelectron is `...........xx10^(-21)J`

A metal surface having a work function phi = 2.2 xx 10^(-19) J , is illuminated by the light of wavelengh 1320Å . What is the maximum kinetic energy ( in eV ) of the emitted photoelectron ? [Take h = 6.6 xx 10^(-34) Js ]

A metal surface having a work function phi = 2.2 xx 10^(-19) J , is illuminated by the light of wavelengh 1320Å . What is the maximum kinetic energy ( in eV ) of the emitted photoelectron ? [Take h = 6.6 xx 10^(-34) Js ]

The work function of a metal is 3.4 eV. A light of wavelength 3000Å is incident on it. The maximum kinetic energy of the ejected electron will be :

Work function of a metal is 3.0 eV. It is illuminated by a light of wavelength 3 xx 10^(-7) m. Calculate the maximum energy of the electron.

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

If the work function for a certain metal is 3.2 xx 10^(-19) joule and it is illuminated with light of frequency 8 xx 10^(14) Hz . The maximum kinetic energy of the photo-electrons would be (h = 6.63 xx 10^(-34) Js)

The photoelectric threshold for some material is 200 nm. The material is irradiated with radiations of wavelength 40 nm. The maximum kinetic energy of the emitted photoelectrons is

The photoeletric threshold 4v is incident on the metal is v. When light of freqency 4v is incident on the metal, the maximum kinetic energy of the emitted photoelectron is

Light of wavelength 200 nm incident on a metal surface of threshold wavelength 400 nm kinetic energy of fastest photoelectron will be

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.