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In YDSE wavelength of light used is 500 ...

In YDSE wavelength of light used is 500 nm and slit width is `0.05 mm`. then the angular fringe width will be.

A

`1.8^@`

B

`3.2^@`

C

`0.57^@`

D

`0.48^@`

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The correct Answer is:
To find the angular fringe width in the Young's Double Slit Experiment (YDSE), we can follow these steps: ### Step 1: Understand the formula for fringe width The fringe width (β) in YDSE is given by the formula: \[ \beta = \frac{\lambda D}{d} \] where: - \( \lambda \) = wavelength of light - \( D \) = distance from the slits to the screen - \( d \) = distance between the slits For angular fringe width, we can relate it to the fringe width using: \[ \text{Angular Fringe Width} = \frac{\beta}{D} \] Thus, we can express the angular fringe width as: \[ \text{Angular Fringe Width} = \frac{\lambda}{d} \] ### Step 2: Convert the given values into standard units Given: - Wavelength (\( \lambda \)) = 500 nm = \( 500 \times 10^{-9} \) m - Slit width (\( d \)) = 0.05 mm = \( 0.05 \times 10^{-3} \) m = \( 5 \times 10^{-5} \) m ### Step 3: Substitute the values into the formula Now, we can substitute the values into the formula for angular fringe width: \[ \text{Angular Fringe Width} = \frac{\lambda}{d} = \frac{500 \times 10^{-9}}{5 \times 10^{-5}} \] ### Step 4: Simplify the expression Calculating the above expression: \[ \text{Angular Fringe Width} = \frac{500 \times 10^{-9}}{5 \times 10^{-5}} = \frac{500}{5} \times \frac{10^{-9}}{10^{-5}} = 100 \times 10^{-4} = 1 \times 10^{-2} \text{ radians} \] ### Step 5: Convert radians to degrees To convert radians to degrees, we use the conversion factor: \[ 1 \text{ radian} = \frac{180}{\pi} \text{ degrees} \] Thus, \[ \text{Angular Fringe Width in degrees} = 1 \times 10^{-2} \times \frac{180}{\pi} \approx 0.57 \text{ degrees} \] ### Final Answer The angular fringe width is approximately \( 0.57 \) degrees. ---
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