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A loop of area 'S' m^2 and N turns carry...

A loop of area 'S' `m^2` and N turns carrying current 'i' is placed in a uniform magnetic field 'B' with its plane parallel to `vecB`. If torque `tau` is experienced by loop due to magnetic field with its plane parallel to `vecB`. If torque `tau` is experienced by loop due to magnetic field find I`vecB` I

A

`tau/ (NiS)`

B

`(Ntau)/(iS)`

C

`(itau)/(NS)`

D

`(Stau)/(Ni)`

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The correct Answer is:
To solve the problem, we need to find the value of the magnetic field \( B \) experienced by a loop of area \( S \) with \( N \) turns carrying a current \( I \) when it is placed in a uniform magnetic field with its plane parallel to \( \vec{B} \). ### Step-by-Step Solution: 1. **Understanding the Torque on the Loop**: The torque \( \tau \) experienced by a current-carrying loop in a magnetic field is given by the formula: \[ \tau = N \cdot I \cdot S \cdot B \cdot \sin(\theta) \] where: - \( N \) = number of turns in the loop - \( I \) = current flowing through the loop - \( S \) = area of the loop - \( B \) = magnetic field strength - \( \theta \) = angle between the magnetic field \( \vec{B} \) and the normal to the plane of the loop. 2. **Identifying the Angle**: Since the plane of the loop is parallel to the magnetic field \( \vec{B} \), the angle \( \theta \) between the magnetic field and the area vector (which is perpendicular to the plane of the loop) is \( 90^\circ \). Therefore, \( \sin(90^\circ) = 1 \). 3. **Simplifying the Torque Equation**: Substituting \( \sin(90^\circ) = 1 \) into the torque equation, we get: \[ \tau = N \cdot I \cdot S \cdot B \] 4. **Rearranging the Equation to Find \( B \)**: To find the magnetic field \( B \), we can rearrange the equation: \[ B = \frac{\tau}{N \cdot I \cdot S} \] 5. **Final Expression**: Thus, the value of the magnetic field \( B \) is given by: \[ B = \frac{\tau}{N \cdot I \cdot S} \] ### Conclusion: The magnetic field \( B \) can be calculated using the above formula, where \( \tau \) is the torque experienced by the loop, \( N \) is the number of turns, \( I \) is the current, and \( S \) is the area of the loop.
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