`6.022 xx 10^22` molecules of compound X has mass 10g.What is molarity of solution containing 5g of 'X' in 2 Lit. solution answer as P(where `M = P xx 10^(-3) mol / lit `)

Answer

To solve the problem, we will follow these steps:

### Step 1: Determine the Molar Mass of Compound X
We know that 6.022 x 10^22 molecules of compound X has a mass of 10 grams.

Using Avogadro's number (6.022 x 10^23), we can find the number of moles in 10 grams of X:
\[ \text{Moles of X} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} = \frac{6.022 \times 10^{22}}{6.022 \times 10^{23}} = \frac{1}{10} \text{ moles} \]

Now, we can find the molar mass (M) using the formula:
\[ \text{Molar Mass} = \frac{\text{Mass}}{\text{Moles}} = \frac{10 \text{ g}}{\frac{1}{10} \text{ moles}} = 100 \text{ g/mol} \]

### Step 2: Calculate Moles of X in 5 grams
Now, we need to find the number of moles in 5 grams of compound X:
\[ \text{Moles of X} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{5 \text{ g}}{100 \text{ g/mol}} = 0.05 \text{ moles} \]

### Step 3: Calculate Molarity of the Solution
Molarity (M) is defined as the number of moles of solute per liter of solution:
\[ \text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} = \frac{0.05 \text{ moles}}{2 \text{ L}} = 0.025 \text{ mol/L} \]

### Step 4: Express Molarity in Terms of P
We are asked to express the molarity in the form \( M = P \times 10^{-3} \) mol/L.

From our calculation:
\[ 0.025 \text{ mol/L} = 25 \times 10^{-3} \text{ mol/L} \]

Thus, \( P = 25 \).

### Final Answer
The value of \( P \) is **25**.

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