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The mean and variance of 5,7,12,10,15,14...

The mean and variance of `5,7,12,10,15,14,a,b` are 10 and 13.5 respectively then value of `|a-b|=`

A

5

B

6

C

7

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first find the values of \(a\) and \(b\) using the given mean and variance, and then calculate \(|a - b|\). ### Step 1: Calculate the Mean The mean of the numbers \(5, 7, 12, 10, 15, 14, a, b\) is given as 10. The formula for the mean is: \[ \text{Mean} = \frac{\text{Sum of all terms}}{\text{Total number of terms}} \] Here, the total number of terms is 8. Thus, we can write: \[ 10 = \frac{5 + 7 + 12 + 10 + 15 + 14 + a + b}{8} \] Calculating the sum of the known numbers: \[ 5 + 7 + 12 + 10 + 15 + 14 = 63 \] Substituting this back into the equation gives: \[ 10 = \frac{63 + a + b}{8} \] Multiplying both sides by 8: \[ 80 = 63 + a + b \] Rearranging gives: \[ a + b = 17 \quad \text{(Equation 1)} \] ### Step 2: Calculate the Variance The variance is given as 13.5. The formula for variance is: \[ \sigma^2 = \frac{\sum x_i^2}{n} - \left(\text{Mean}\right)^2 \] Substituting the known values: \[ 13.5 = \frac{5^2 + 7^2 + 12^2 + 10^2 + 15^2 + 14^2 + a^2 + b^2}{8} - 10^2 \] Calculating the squares of the known numbers: \[ 5^2 = 25, \quad 7^2 = 49, \quad 12^2 = 144, \quad 10^2 = 100, \quad 15^2 = 225, \quad 14^2 = 196 \] Now, summing these squares: \[ 25 + 49 + 144 + 100 + 225 + 196 = 839 \] Substituting this into the variance equation gives: \[ 13.5 = \frac{839 + a^2 + b^2}{8} - 100 \] Multiplying both sides by 8: \[ 108 = 839 + a^2 + b^2 - 800 \] This simplifies to: \[ a^2 + b^2 = 169 \quad \text{(Equation 2)} \] ### Step 3: Solve for \(a\) and \(b\) We have two equations now: 1. \(a + b = 17\) (Equation 1) 2. \(a^2 + b^2 = 169\) (Equation 2) From Equation 1, we can express \(b\) in terms of \(a\): \[ b = 17 - a \] Substituting this into Equation 2: \[ a^2 + (17 - a)^2 = 169 \] Expanding the equation: \[ a^2 + (289 - 34a + a^2) = 169 \] Combining like terms: \[ 2a^2 - 34a + 289 - 169 = 0 \] This simplifies to: \[ 2a^2 - 34a + 120 = 0 \] Dividing the entire equation by 2: \[ a^2 - 17a + 60 = 0 \] ### Step 4: Factor the Quadratic Now we factor the quadratic: \[ (a - 12)(a - 5) = 0 \] Thus, we have: \[ a = 12 \quad \text{or} \quad a = 5 \] Using \(a + b = 17\): - If \(a = 12\), then \(b = 5\). - If \(a = 5\), then \(b = 12\). ### Step 5: Calculate \(|a - b|\) Now we calculate \(|a - b|\): \[ |a - b| = |12 - 5| = 7 \] ### Final Answer Thus, the value of \(|a - b|\) is: \[ \boxed{7} \]
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