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Bus moving with speed v forwards a stationary wall. it produces sound of frequency `f = 420 Hz. The heard frequency of reflected sound from wall by driver is `490 Hz`. Calculate the speed v of bus. The velocity of sound in air is `330 m/s`.

A

`61 Km/s`

B

`71 Km/s

C

`81 Km/s`

D

`91 Km/s`

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The correct Answer is:
To solve the problem, we can use the Doppler effect formula for sound. The situation involves a moving source (the bus) and a stationary observer (the wall). The steps to find the speed of the bus are as follows: ### Step 1: Understand the given values - Frequency of sound produced by the bus (f1) = 420 Hz - Frequency of sound heard by the driver after reflection (f2) = 490 Hz - Velocity of sound in air (c) = 330 m/s ### Step 2: Set up the Doppler effect equations When the bus is moving towards the wall, the frequency of the sound heard by the wall (f1) is given by: \[ f_1 = f \left( \frac{c}{c - v} \right) \] Where: - \( f \) is the original frequency (420 Hz) - \( v \) is the speed of the bus When the sound reflects off the wall and travels back to the bus, the frequency heard by the driver (f2) is given by: \[ f_2 = f_1 \left( \frac{c + v}{c} \right) \] ### Step 3: Substitute the known values From the first equation: \[ 420 = f \left( \frac{330}{330 - v} \right) \] From the second equation: \[ 490 = 420 \left( \frac{330 + v}{330} \right) \] ### Step 4: Solve the second equation for v Rearranging the second equation: \[ 490 = 420 \left( \frac{330 + v}{330} \right) \] \[ \frac{490}{420} = \frac{330 + v}{330} \] \[ \frac{49}{42} = \frac{330 + v}{330} \] Cross-multiplying gives: \[ 49 \cdot 330 = 42 \cdot (330 + v) \] ### Step 5: Expand and simplify Expanding the equation: \[ 16170 = 13860 + 42v \] Rearranging gives: \[ 16170 - 13860 = 42v \] \[ 2310 = 42v \] \[ v = \frac{2310}{42} \] \[ v = 55 \text{ m/s} \] ### Step 6: Convert to km/h To convert the speed from m/s to km/h: \[ v_{km/h} = v_{m/s} \times \frac{18}{5} \] \[ v_{km/h} = 55 \times \frac{18}{5} = 198 \text{ km/h} \] ### Final Answer The speed of the bus is approximately **198 km/h**. ---
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