For the following redox reactions
i) `2Fe^(2+) + H_2O_2 rarr xA + yB`
ii) `2MnO_4^- + 6H^+ + 5H_2O_2 rarr pA+ qB + rC`
so sum of (x+y+p+q+r)

Answer

To solve the given redox reactions and find the sum of the coefficients \(x + y + p + q + r\), we will analyze each reaction step by step.

### Reaction i:
\[ 2Fe^{2+} + H_2O_2 \rightarrow xA + yB \]

1. **Identify the oxidation states**:
- In \(Fe^{2+}\), iron is in the +2 oxidation state.
- In \(H_2O_2\), the oxidation state of oxygen is -1.

2. **Determine the products**:
- \(Fe^{2+}\) is oxidized to \(Fe^{3+}\).
- \(H_2O_2\) is reduced to \(OH^-\).

3. **Write the half-reactions**:
- Oxidation half-reaction:
\[ Fe^{2+} \rightarrow Fe^{3+} + e^- \]
(2 moles of \(Fe^{2+}\) will produce 2 moles of \(Fe^{3+}\))
- Reduction half-reaction:
\[ H_2O_2 + 2e^- \rightarrow 2OH^- \]

4. **Balance the half-reactions**:
- For every 2 moles of \(Fe^{2+}\), we need 1 mole of \(H_2O_2\).
- The balanced reaction is:
\[ 2Fe^{2+} + H_2O_2 \rightarrow 2Fe^{3+} + 2OH^- \]

5. **Identify coefficients**:
- Here, \(x = 2\) (for \(Fe^{3+}\)) and \(y = 2\) (for \(OH^-\)).

### Reaction ii:
\[ 2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow pA + qB + rC \]

1. **Identify the oxidation states**:
- In \(MnO_4^-\), manganese is in the +7 oxidation state.
- In \(H_2O_2\), the oxidation state of oxygen is -1.

2. **Determine the products**:
- \(MnO_4^-\) is reduced to \(Mn^{2+}\).
- \(H_2O_2\) is oxidized to \(O_2\).

3. **Write the half-reactions**:
- Reduction half-reaction:
\[ MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O \]
- Oxidation half-reaction:
\[ 5H_2O_2 \rightarrow 5O_2 + 10H^+ + 10e^- \]

4. **Balance the half-reactions**:
- The overall balanced reaction combining both half-reactions is:
\[ 2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow 2Mn^{2+} + 8H_2O + 5O_2 \]

5. **Identify coefficients**:
- Here, \(p = 2\) (for \(Mn^{2+}\)), \(q = 8\) (for \(H_2O\)), and \(r = 5\) (for \(O_2\)).

### Final Calculation:
Now, we sum the coefficients:
\[ x + y + p + q + r = 2 + 2 + 2 + 8 + 5 = 19 \]

### Answer:
The sum of the coefficients \(x + y + p + q + r\) is **19**.