Which of the following compounds will form the precipitate with `aq. AgNO_(3)` solution most readily?

Options

A.
B.
C.
D.

Answer

To determine which compound will form a precipitate with aqueous AgNO₃ solution most readily, we need to consider the nature of the compounds and how they interact with silver ions (Ag⁺) in solution. Silver nitrate is known to react with halides to form insoluble silver halides, which precipitate out of solution.

### Step-by-Step Solution:

1. **Identify the Compounds**:
List the compounds given in the question. For example, let's assume the compounds are:
- R₃H₂Cl (a chloride)
- R₃H₂Br (a bromide)
- R₃H₂I (an iodide)
- R₃H₂F (a fluoride)

2. **Understand the Precipitation Reaction**:
The general reaction for a halide with AgNO₃ can be written as:
\[ R₃H₂X + AgNO₃ \rightarrow R₃H₂NO₃ + AgX(s) \]
where X is a halide (Cl, Br, I, F).

3. **Consider Solubility of Silver Halides**:
The solubility of silver halides in water decreases in the order:
- AgF > AgCl > AgBr > AgI
This means that AgI is the least soluble and will precipitate out of solution most readily, followed by AgBr, AgCl, and finally AgF.

4. **Determine the Most Readily Precipitating Compound**:
From the list of halides, the iodide (R₃H₂I) will form AgI, which is the least soluble and will precipitate most readily when reacted with AgNO₃.

5. **Conclusion**:
Therefore, the compound that will form a precipitate with aqueous AgNO₃ solution most readily is R₃H₂I.

### Final Answer:
The compound that will form the precipitate with `aq. AgNO₃` solution most readily is R₃H₂I (iodide).