A prism of angle `A = 1^(@)` has a refractive index `mu = 1.5` . A good estimate for the minimum angle of deviation ( in degrees ) is close to N/10 value of N is ________ .

A prism of apex angle A=60^@ has the refractive index mu=sqrt2. The angle of incidence for minimum deviation is

A prism of refracting angle 4^(@) is made of a material of refractive index 1.652. Find its angle of minimum deviation.

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is

There is prism of refractive index 1.5 and prism angle 2 degree . Find minimum deviation caused by this prism

A prism is made up of material of refractive index sqrt3 . The angle of prism is A . If the angle of minimum deviation is equal to the angle of the prism, then the value of A is

A thin prism of angle 15^(@) made of glass of refractive index mu_(1)=1.5 is combined with another prism of glass of refractive index mu_(2)=1.75 . The combination of the prism produces dispersion without deviation. The angle of the second prism should be

A prism is made of glass of refractive index 1.5. If the angle of minimum deviation is equal to the refracting angle of the prism, calculate the angle of the prism.

A prism of refractive index m and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A , then the value of A in terms of m is

A prism has refractive index sqrt((3)/(2)) and refractive angle 90^@ . Find the minimum deviation produced by prism

The correct relation between the refractive index ( mu ) of the material of prism (A) and angle of minimum deviation ( delta ) is