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The complex that can show optical activi...

The complex that can show optical activity is :

A

`cis-[CrCl_(2)(o x)_(2)]^(3-)" (ox = oxalate)"`

B

`trans - [Fe(NH_(3))_(2)(CN)_(4)]^(-)`

C

`trans - [Cr(Cl_(2))(o x)_(2)]^(3-)`

D

`cis - [Fe(NH_(3))_(2)(CN)_(4)]^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which complex can show optical activity, we need to analyze the given options based on the criteria for optical activity. A complex is optically active if it has a non-superimposable mirror image and lacks any type of symmetry (like a plane of symmetry or a center of symmetry). Let's analyze each option step by step: ### Step 1: Analyze the first option - **Cis-chromium chloride oxalate** - Structure: This is an octahedral complex with two oxalate ligands and two chloride ligands in the cis position. - Symmetry: When we draw the structure, we see that there is no plane of symmetry. The two oxalate ligands and two chloride ligands are arranged such that if we place a mirror behind it, the image will not superimpose on the original structure. - Conclusion: This complex is optically active. ### Step 2: Analyze the second option - **Trans-NH3 twice CN4** - Structure: This complex has four cyanide ligands in a horizontal plane and two ammine ligands in a vertical position. - Symmetry: The horizontal plane acts as a plane of symmetry, making the upper and lower parts identical. - Conclusion: This complex is optically inactive. ### Step 3: Analyze the third option - **Trans-chromium oxalate** - Structure: Similar to the previous one, this complex has two oxalate ligands and two chloride ligands in a trans position. - Symmetry: The horizontal plane again serves as a plane of symmetry, making the upper and lower parts identical. - Conclusion: This complex is optically inactive. ### Step 4: Analyze the fourth option - **Cis-iron NH3 twice CN4** - Structure: The two ammine ligands are positioned side by side, while the cyanide ligands are arranged in a way that could potentially allow for symmetry. - Symmetry: A plane can be drawn through the vertical axis that divides the complex into two identical halves. - Conclusion: This complex is optically inactive. ### Final Conclusion: After analyzing all the options, we find that the only complex that can show optical activity is **Cis-chromium chloride oxalate**. ---

To determine which complex can show optical activity, we need to analyze the given options based on the criteria for optical activity. A complex is optically active if it has a non-superimposable mirror image and lacks any type of symmetry (like a plane of symmetry or a center of symmetry). Let's analyze each option step by step: ### Step 1: Analyze the first option - **Cis-chromium chloride oxalate** - Structure: This is an octahedral complex with two oxalate ligands and two chloride ligands in the cis position. - Symmetry: When we draw the structure, we see that there is no plane of symmetry. The two oxalate ligands and two chloride ligands are arranged such that if we place a mirror behind it, the image will not superimpose on the original structure. - Conclusion: This complex is optically active. ...
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JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS 2020-CHEMSITRY
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