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Let C(NaCl) and C(BaSO(4)) be the conduc...

Let `C_(NaCl) and C_(BaSO_(4))` be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO4, respectively, at a temperature T.
Which of the following is false?

A

`C_(NaCl)(T_(2))gtC_(NaCl)(T_(1))" for "T_(2) gt T_(1)`

B

`C_(BaSO_(4))(T_(2))gtC_(BaSO_(4))(T_(1))" for "T_(2) gt T_(1))`

C

Ionic mobilities of ions form both salts increase with T.

D

`C_(NaCl)gt gt C_(BaSO_(4))` at a given T

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The correct Answer is:
To solve the problem, we need to analyze the conductance of saturated aqueous solutions of NaCl and BaSO4 and determine which statement is false based on the information provided. ### Step-by-Step Solution: 1. **Understanding Conductance**: Conductance (C) is a measure of how well a solution can conduct electricity. It depends on the concentration and mobility of the ions in the solution. 2. **Dissociation of Compounds**: - NaCl dissociates into Na⁺ and Cl⁻ ions in solution. - BaSO₄ dissociates into Ba²⁺ and SO₄²⁻ ions in solution. 3. **Ionic Size and Mobility**: - Na⁺ is a smaller ion compared to Ba²⁺. Smaller ions typically have higher mobility in solution because they can move more freely. - However, the mobility of ions is also affected by the solvation process, where water molecules surround the ions. 4. **Effect of Solvation**: - In aqueous solutions, smaller ions like Na⁺ can form a more extensive solvation shell due to their charge density, which can hinder their movement. - Larger ions like Ba²⁺ may not form as extensive a solvation shell and can move more freely, resulting in higher conductance. 5. **Comparison of Conductance**: - At a given temperature, the conductance of NaCl (C_NaCl) can be less than that of BaSO₄ (C_BaSO₄) due to the reasons discussed. - However, in a molten state, the conductance of NaCl is higher than that of BaSO₄ because the ions are not solvated and can move freely. 6. **Identifying the False Statement**: - The statement that "the conductance of NaCl is less than the conductance of BaSO₄ in aqueous solution" is true. - The statement that "the conductance of NaCl is greater than that of BaSO₄ in molten state" is also true. - Therefore, if any statement claims that the conductance of NaCl is greater than BaSO₄ in aqueous solution, that would be false. ### Conclusion: The false statement is that the conductance of NaCl is greater than that of BaSO₄ in saturated aqueous solutions.

To solve the problem, we need to analyze the conductance of saturated aqueous solutions of NaCl and BaSO4 and determine which statement is false based on the information provided. ### Step-by-Step Solution: 1. **Understanding Conductance**: Conductance (C) is a measure of how well a solution can conduct electricity. It depends on the concentration and mobility of the ions in the solution. 2. **Dissociation of Compounds**: - NaCl dissociates into Na⁺ and Cl⁻ ions in solution. ...
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A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)) . For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-) , with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y) . While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp) , value at a particular temperature, then precipitation occurs. The solubility of BaSO_(4) , in 0.1 M BaCl_(2) , solution is (K_(sp) , of BaSO_(4), = 1.5 xx 10^(-9))

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