Orthogonal Trajectories

Illustration Based on Exact Differential Equation Mixture Problems || Orthogonal Trajectory

Illustration Based on Exact Differential Equation Mixture Problems and Orthogonal Trajectory

Any curve which cuts every member of a given family of curve is called an orthogonal trajectory of family. To get this, we replace (dy)/(dx)by -(dx)/(dy) in differential equation. The orthogonal trajectories for y=ce^(-x) represent

Any curve which cuts every member of a given family of curve is called an orthogonal trajectory of family. To get this, we replace (dy)/(dx) by -(dx)/(dy) in differential equation. The orthogonal trajectories for y=cx^(2) , where c is a constant is

Exact differential equation || Orthogonal trajectory

If (2, 4) is a point on the orthogonal to trajectory of x^(2) + y^(2) - ay = 0 , then the orthogonl trajectory is a circle with radius__________

Find the orthogonal trajectory of y^(2)=4ax (a being the parameter).

The orthogonal trajectory of the family of parabolas y^2 =4ax is

STATEMENT-1 : The orthogonal trajectory of a family of circles touching x-axis at origin and whose centre the on y-axis is self orthogonal. and STATEMENT-2 : In order to find the orthogonal trajectory of a family of curves we put -(dx)/(dy) in place of (dy)/(dx) in the differential equation of the given family of curves.