Home
Class 11
PHYSICS
The value of acceleration due to gravity...

The value of acceleration due to gravity `(g)` at height `h` above the surface of earth is given by
`g^'=(gR^2)/((R+h)^2)`. If `hlt ltR`, then prove that `g^'=g(1-(2h)/(R))`.

Promotional Banner

Topper's Solved these Questions

  • Mathematical tools

    SL ARORA|Exercise Exercise|20 Videos

  • LAWS OF MOTION : FRICTION

    SL ARORA|Exercise Self Practice|95 Videos

  • Mechanical Properties of fluids

    SL ARORA|Exercise Exercise|459 Videos

Similar Questions

Explore conceptually related problems

The value of acceleration due to gravity (g) at height h above the surface of earth is given as g^()=(gR)^(2)/((R+h))^(2) If h lt lt R , then prove that g^()=g(1-(2h)/(R))

Find ratio of acceleration due to gravity g at depth d and at height h where d=2h

Let g be the acceleration due to gravity on the earth's surface.

The acceleration due to gravity at a height h above the surface of the earth has the same value as that at depth d= ____below the earth surface.

If R is the radius of the earth, then the value of acceleration due to gravity at a height h from the surface of the earth will become half its value on the surface of the earth if

The value of the acceleration due to gravity is g1 at a height h=(R)/(2)(R= radius of the earth) from the surface of the earth.It is again equal to (g1/2) at a depth d below the surface of the earth.The ratio d/R equals:

What is the acceleration due to gravity at a height h ( = radius of the earth) from the surface of the earth ? ltbgt (g=9.8m//s^(2))

The value of the acceleration due to gravity is g_(1) at a height h=(R)/(2) (R=radius of the earth) from the surface of the earth.It is equal to 2g_(1) at a depth d below the surface of the earth.The ratio ((d)/(R)) is equal to:

Given, acceleration due to gravity on surface of earth is g. if g' is acceleration due to gravity at a height h above the surface of earth, then

Given g_(d) = g(1-(d)/(R)) where gd and g are the accelerations due to gravity at a depth 'd' km, and on the surface of the Earth, respectively, R is the radius of the Earth, then the depth at which g_(d) = (g)/(2) is______.

SL ARORA-Mathematical tools-Exercise
  1. The value of acceleration due to gravity (g) at height h above the sur...

    Text Solution

    |

  2. Find dy/dx for the following functions:y= x^3- 3x^2 + 3x - (2/5).

    Text Solution

    |

  3. Find dy/dx for the following functions:y= ((x-1)(x-2))/sqrtx.

    Text Solution

    |

  4. Find dy/dx for the following functions: y= (sqrt x + (1/sqrt x))^2.

    Text Solution

    |

  5. Differentiate the following functions: (x^2 -4x +5)(x^3 -2).

    Text Solution

    |

  6. Differentiate the following functions:((2x +3)/(x^2-5)).

    Text Solution

    |

  7. Differentiate the following functions: ((sin x+ cosx)/(sin x - cos x).

    Text Solution

    |

  8. Differentiate the following functions: (4x^3 - 5x^2 + 1)^4.

    Text Solution

    |

  9. If the motion of aparticle is governed by the equation, s= 2t^3- 3t^2+...

    Text Solution

    |

  10. The angular displacement of a particle performing circular motion is ...

    Text Solution

    |

  11. Show that force can be expressed as the product of mass and accelerati...

    Text Solution

    |

  12. Integrate the following: 6x + 5x^2 - 2x^3 + (1/x^2)

    Text Solution

    |

  13. Integrate the following: ax^2 +bx+c

    Text Solution

    |

  14. Integrate the following:(x+(1/x))^3

    Text Solution

    |

  15. Integrate the following: 3 cosec^2 x- 5x+ sinx)

    Text Solution

    |

  16. Integrate the following: 3cosec^2 x +2sin 3x)

    Text Solution

    |

  17. Evaluate the following integrals:

    Text Solution

    |

  18. Evaluate the following integrals:

    Text Solution

    |

  19. Evaluate the following integrals:

    Text Solution

    |

  20. Evaluate the following integrals:

    Text Solution

    |

  21. Evaluate the following integrals:

    Text Solution

    |