A particle starts rotating from rest according to the formuls, `theta=((3t^3)/20 ) - ((t^2)/3))` where `theta` is in radian and t is second. Find the angular velocity to and angular acceleration a at the end of 5 seconds.

A particle is at rest, It starts rotating about a fixed point. Its angle of rotation (theta) with time (t) is given by the relation : theta = (6t^3)/(15) - (t^2)/(2) where theta is in radian and t is seconds. Find the angular velocity and angular acceleration of a particle at the end of 6 second.

The angular displacement of a particle performing circular motion is theta=(t^(3))/(60)-(t)/(4) where theta is in radian and 't' is in second .Then the angular velocity and angular acceleraion of a particle at the end of 5 s will be

A solid body rotates about a stationary axis accordig to the law theta=6t-2t^(3) . Here theta , is in radian and t in seconds. Find (a). The mean values of thhe angular velocity and angular acceleration averaged over the time interval between t=0 and the complete stop. (b). The angular acceleration at the moment when the body stops. Hint: if y=y(t) . then mean/average value of y between t_(1) and t_(2) is ltygt=(int_(t_(1))^(t_(2))y(t)dt))/(t_(2)-t_(1))

A particle starts rotating from rest. Its angular displacement is expressed by the following equation theta=0.025t^(2)-0.1t where theta is in radian and t is in seconds. The angular acceleration of the particle is

Angular position theta of a particle moving on a curvilinear path varies according to the equation theta=t^(3)-3t^(2)+4t-2 , where theta is in radians and time t is in seconds. What is its average angular acceleration in the time interval t=2s to t=4s ?

The angular displacement of a particle performing circular motion is theta=(t^(4))/(60)-(t)/(4) where theta is radian and 't' is in seconds. Then the acceleration of a particle at the end of 10 s will be

The displacement of a particle moving in a circular path is given by theta = 3 t^(2) + 0.8 , where theta is in radian and t is in seconds . The angular velocity of the particle at t=3 sec . Is

A angular positio of a point on the rim of a rotating wheel is given by theta=4t-3t^(2)+t^(3) where theta is in radiuans and t is in seconds. What are the angualr velocities at (a). t=2.0 and (b). t=4.0s (c). What is the average angular acceleration for the time interval that begins at t=2.0s and ends at t=4.0s ? (d). What are the instantaneous angular acceleration at the biginning and the end of this time interval?

IF the equation for the displancement of a particle moving on a circular path is given by theta=2t^3+0.5 , where theta is in radius and t is in seconds, then the angular velocity of the particle at t=2 s is