The parallax of a heavenly body measured...

The parallax of a heavenly body measured from two points diametrically opposite on equator of earth is 1.0 minutes. If the radius of the earth is 6400 km, find the distance of the heavenly body from the centre of the earth in AU. Given `1 AU=1.5xx10^(11)`m.

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The parallex of a heavenly body measured ffrom two points diametrically opposite on equater of earth is 1.0 minutes. If the radius of the earth is 6400 m, find the distance of the heavenly body from the centre of the earth in AU. Given 1 AU=1.5xx10^(11) m.

The parallax of a heavenly body measured from tow points diametrically opposite on equator of earth is 2.0 minute. If radius of earth is 6400 km, calculate distance of heavenly body.

The surface density of charge on the earth's surface is 2.65xx10^(-9)C//m^(2) . If the radius of the earth is 6400 km then the charge carried by the earth is

The magnetic field at a point on magnetic equator is 3*1xx10^-5T . If radius of earth is taken as 6400km , what is magnetic moment of the assumed dipole at the centre of earth?

The moon is observed from two diametrically extremes A and B on earth. The angle of parallax is found to be 1^@54' . If the diameter of the earth is about 1.276 xx 10^7 m, estimate the distance of the moon from the earth.

A certain planet's year is 8 times the earth's year. Find the distance of this planet from the sun if the distance of the earth is 1 AU from the sun.

The energy required for a body of mass 1000 kg to escape from the attraction of the earth is (If radius of the earth is 6400 km and g=10m//s^(2) )

What is the linear velocity of a body on the surface of the earth at the equator ? Given the radius of the earth is 6400 km . Period of rotation of the earth = 24 hours.

The moon subtends an angle of 57 minutes at the base line equal to radius of earth. What is the distance of moon from earth. Given radius of earth is 6400 km.

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