Assuming that a planet goes round the sun in a circular orbit of radius `0.5AU` determine the angle of maximum elongation for the planet and its distance from the earth when elongation is measured.

Assuming that the orbit of the planet Mercury around the sun to be a circle, Copernicus detrmined the orbital radius to be 0.38AU . From this determine the angle of maximum elongation for Mercury and its distance from the earth when the elongation is maximum .

Assume that the earth goes round the sun in a circular orbit with a constant speed of 30 km/s

If a planet of mass m is revolving around the sun in a circular orbit of radius r with time period, T then mass of the sun is

For planets revolving round the sun, show that T^(2) prop r^(3) , where T is the time period of revolution of the planet and r is its distance from the sun.

When the earth revolves round the sun in an elliptical orbit, its kinetic energy is

A planet is revolving round the sun in an elliptical orbit, If v is the velocity of the planet when its position vector from the sun is r, then areal velocity of the planet is

A plantet is moving round the sun in an elliptical orbit as shows. As the planet moves from a to B

A planet moves around the sun in an elliptical orbit. When earth is closest from the sun, it is at a distance r having a speed v . When it is at a distance 4r from the sun its speed will be: