In the equation y= a sin (`omega`t+ kx) where t and x stand for time and distance respectively. What are the dimensions of `omega`/k?

In the equation y= a sin (omega t+ kx) t and x stand for time and distance respectively. What are the dimensions of omega//k ?

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

The equation y=A sin^2 (kx-omega t) represents a wave with

In the expression y = a sin (omega t + theta ) , y is the displacement and t is the time . Write the dimension of a , omega and theta .

(a) the displacement of a particle is given by s - a sin (omega t = kx) , where t is in second and x is in meter. Find the dimensions of omega and k . (b) The velocity of a praticle is given by v = v_(0) e^(-lambda t) , where t is time. Find the dimensions of v_(0) and lambda .

Equation y=y_(0) sin (Kx+omega t) represents a wave :-

In the equation y = A sin (omega t - kx), obtain the dimensional formula of omega and k. Given x is distnace and t is time.

The displacement of a progressive wave is represented by y = A sin (omegat - kx), where x is distance and t is time. Write the dimensional formula of (i) omega and (ii) k.

if y = A sin(omega t - kx) , then the value of (dy)/(dx) is

In a wave equation, given by y = A sin (omega t - Kx), y cannot represent