Two resistances `R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega` are connected in series . Find the equivalent resistance of the series combination.

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

Two resistance R_(1)=100pm 3Omega and R_(2)=200pm4Omega are connected in seriesg. What is their equivalent resistance?

The resistors of resistances R_(1)=100pm3" ohm and R"_(2)=200pm 4ohm are connected in series. The equivalent resistance of the series combination is

Two resistors of resistances R_(1)=100 pm 3 ohm and R_(2)=200 pm 4 ohm are connected (a) in series, (b) in parallel. Find the equivalent resistance of the (a) series combination, (b) parallel combination. Use for (a) the relation R=R_(1)+R_(2) and for (b) 1/(R')=1/R_(1)+1/R_(2) and (Delta R')/R'^(2)=(Delta R_(1))/R_(1)^(2)+(Delta R_(2))/R_(2)^(2)

Tow resistance R_(1) = 50 pm 2 ohm and R_(2) = 60 pm connected in series , the equivalent resistance of the series combination in

Two resistance (200 pm 4) Omega and (150 pm 3) Omega are connected in series . What is their equivalent resistance ?

Two resistors R_1 = (4 pm 0.8) Omega and R_2 (4 pm 0.4) Omega are connected in parallel. The equivalent resistance of their parallel combination will be :

Two conductors of resistance R_(1) (50 +- 2) ohm and R_(2) = (100 +- 4) ohm are connected in (a) series and (b) parallel. Find the equivalent resistance.

Two resistor R_(1) = (24 +- 0.5)Omega and R_(2) = (8 +- 0.3)Omega are joined in series, The equivalent resistence is