The lengths of two rods are `15.2+-0.2 cm` and `10.7+-0.2 cm` Find difference in lengths of the two rods with the limits of error.

The lengths of two rods are recorded as l_(1)=25.2pm0.1cm and l_(2)=16.8pm0.1cm . Find the sum of the lengths of the two rods with the limits of error.

Consider a brass rod and a steel rod (80 cm longer than brass rod) at 0^(@)C . It is observed that on increasing temperatures of the two rods by same amount difference in lengths of the two rods does not change. Given that the thermal coefficient of linear expansion for steel and brass are 11xx10^(-6).^(@)C^(-1) and 19xx10^(-6).^(@)C^(-1) respectively. The sum of lengths of the two rods at 0^(@)C is

The lenghts of two cylinders are measured to be i_1 = (5.62 +- 0.01) cm and I_2 = (4.34 +- 0.02) cm. Calculate difference in lengths with error limtits.

The lengths of the two pieces of wire are l_1 =(35.2 +- 0.1) cm and l_2 = (47.4 +- 0.2) cm. what is the total length of wire with error limits ?

The length of two rods are recorded as l_(1) = (25.2 pm 0.1) cm and l_(2) = (16.8 pm 0.1) cm . Find their combined length .

The lengths and breadth of a rectangle are (5.7 +- 0.1)cm and (2.4 +- 0.2) cm. Calculate area of the rectangle with error limits.

The sides of a rectangle are (10.5 +- 0.2) cm and ( 5.2 +- 0.1 ) cm . Calculate its perimeter with error limits .

The lengths of the sides of a rectangle are (5.7 +- 0.2)cm and (3.2 +- 0.1) cm. Calculate the perimeter of rectangular with error limits.