The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage error in `R`.

The resistance R = (V )/(i) , where V=(50 pm 2.0)V and I=(20pm 0.2)A. The percentage error in R is ’x’% The value of 'x' to the nearest integer is "_________"

The resistance R=(V)/(I) where V=(200+-5)V and I=(20+-0.2)A ,the percentage error in the measurement of "R" is :

The resistance of a conductor R = V//I , where V = (50 +- 2) V and I = (9 +- 0.3) A . Find the percentage error in R .

The resistance R = V//i , where V = 100 +- 5 V and I = 10+- 0.2 A . What is the total error in R ?

The resistance R=(V)/(I) , whereV= 100pm5V and I=10pm0.2A . The pressure error in V is 5% and in I is 2%. What is the total percentage error in R?

If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

The resistance R of a conductor is defind as the ratio of the potential difference applied across it to the current flowing through ti . If V = (100 pm 5) V and I = (5 + 0.1) A , what is the percentage error in R ?

When the voltage and current in a conductor are measured as (100pm4 ) V and (5pm0.2 ) A, then the percentage of error in the calculation of resistance is

[" According to ohms law "V=iR" ,"],[" where "V" is potential "],[" difference,"l=" electric current "],[" and "R=" resistance.If "],[V=(220+-11)" volt and "],[i=(10+-0.1)" ampere and "],[" percentage error in the "],[" measurement of "R" is "n%" then "],[" find the value of "n" ? "]