A physical quantity `P = a^3b^2/cd`. If the percentageerrors in the measurement of a, b, c and d are 1%, 2%, 3% and 4% then the percentage error in P______.

.A physical quantity P=A^(3)B^(2)/CD ,If the percentage errors in the measurement of A,B,C and Dare 1%,2%,3% and 4% then what is the maximum error in the measurement of P

A physical quantity P is related to four observables a, b, c and d as P=a^(3)b^(2)//sqrtcd . The percentage errors in the measurements of a, b, c and d are 1%, 3% 4% and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using this formula turns out to be 3.763 , to what value should you round off the result?

A Physical quantity P is given by P= (A^2sqrtB)/C , and the percentage errors in the measurements of A, B and C are 1% , 2 % and 4% respectively. Find the percentage error in P.

A physcial quantity X is related to four measurable quantites a, b, c and d as follows : X = a^2 b^3 c^(5//2) d^(-2) The percentage error in the measurement of a, b, c and d are 1% , 2%, 3% and 4%, respectively. What is the percentage error in quantity X ? if the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result ?

If P=a^2*b^3*c*d^1/2 and the percentage error in a,b,c and d are 1%,2%,3% and 4% respectively.Find percentage error in P.

A physical quantity X is related to four measurable quantities a,b,c and d as follows X=a^2b^3c^((5)/(2))d^-2 . The percentage error in the measurement of a,b,c and d are 1%,2%,3% and 4% repectively. What is the percentage erroe in quantity X? If the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result.

A physical quantity Y is expressed as Y= (p^2)/(r )((q)/(sqrt(s)))^3 If the percentage error in the measurement of p,q,r and s are 4%, 2%, 1% and 3% respectively, caluclate the percentage error in Y.