Calcualte the fractional error `((Deltax)/x)`, if `x=a^(n)`,

A physcial quantity x =a^2 b^(-3//2)/(c^4) has a relative error (Deltax)/(x) =2(Deltaa)/(a) - (3)/(2) (Deltab)/(b) -4(Deltac)/(c ) .is the statement correct?

If {x} denotes the fractional part of x, then {(3^(2n))/(8)},n in N, is

A physical quantity rho is calculated by using the formula rho =(1)/(10)(xy^(2))/(z^(1//3)) , where x, y and z are experimentally measured quantities. If the fractional error in the measurement of x, y and z are 2%, 1% and 3% , respectively, then the maximum fractional error in the calculation of rho is

As is known, the result of an experiment is calculated by performing mathematical operation (like addition, subtraction, multiplication, division, etc.) on several measurements, which have different degrees of accuracy. It has been established that (a) When x= a+b , Delta x = +- (Delta a + Delta b) (b) When x= a -b , Delta x = +- (Delta a + Deltab) (c ) When x = axxb , (Deltax)/(x) = +- ((Deltaa)/(a) +(Deltab)/(b)) (d) When x = (a)/(b) , (Deltax)/(x) = +-((Deltaa)/(a) + (Deltab)/(b)) Read the above paragraph and answer the following questions : (i) Why is absolute error in x = (a -b) , sun of the absolute error in a and b ? (ii) Why is fractional error in x=(a)/(b) , sun of fractional error in a and b ? (iii) What do you learn from this ?

If {x} denotes the fractional part of x then 30xx{(4^(2n))/(15)},n is equal to

Show that the maximum fractional error in the product of two quantities is equal to the sim of the fractional errors in the individual quantities.

What is the fractional error in g calculated from T = 2 pi sqrt((l)/(g)) ? Given that fractional error in T and l are pm x and pm y respectively.

If y=x^(n), then the ratio of relative errors in y and x is (a)1:1 (b) 2:1 (c) 1:n (d) n:1