Home
Class 11
PHYSICS
The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum is `T = 2pisqrt((L)/(g))`. Meaured value of `L` is `20.0 cm` know to `1mm` accuracy and time for `100` oscillation of the pendulum is found to be `90 s` using a wrist watch of `1 s` resolution. The accracy in the determinetion of `g` is :

A

0.02

B

0.03

C

0.01

D

0.05

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • Units and Measurements

    SL ARORA|Exercise Exercise|499 Videos
  • THERMODYNAMICS

    SL ARORA|Exercise Exercise|342 Videos
  • VECTORS

    SL ARORA|Exercise Problems For Self Practice|56 Videos

Similar Questions

Explore conceptually related problems

The period of oscillation of a simple pendulum is T = 2pisqrt(L//g) . Measured value of L is 20.0 cm known to 1mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

The time period of a simple pendulum is given by T = 2pisqrt(l/g) . The measured value of the length of pendulum is 10 cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to the nearest integer is,

The period of oscillation of a simple pendulum is T = 2 pi sqrt((L)/(g)) .L is about 10 cm and is known to 1mm accuracy . The period of oscillation is about 0.5 s . The time of 100 oscillation is measured with a wrist watch of 1 s resolution . What is the accuracy in the determination of g ?

The time period of a simple pendulum is given by T = 2 pi sqrt(L//g) , where L is length and g acceleration due to gravity. Measured value of length is 10 cm known to 1 mm accuracy and time for 50 oscillations of the pendulum is 80 s using a wrist watch of 1 s resloution. What is the accuracy in the determination of g ?

The period of oscillation of a simple pendulum is T = 2pi sqrt(L/g) . Measured value of 'L' is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of 'g' will be :

The period of oscillation of a simple pendulum is given by T=2pisqrt((l)/(g)) where l is about 100 cm and is known to have 1 mm accuracy. The period is about 2 s. The time of 100 oscillation is measrued by a stop watch of least count 0.1 s. The percentage error is g is

The time period of a pendulum is given by T = 2 pi sqrt((L)/(g)) . The length of pendulum is 20 cm and is measured up to 1 mm accuracy. The time period is about 0.6 s . The time of 100 oscillations is measured with a watch of 1//10 s resolution. What is the accuracy in the determination of g ?

The time period of oscillation of simple pendulum is given by t = 2pisqrt(I//g) What is the accurancy in the determination of 'g' if 10cm length is knownj to 1mm accuracy and 0.5 s time period is measured form time of 100 oscillations with a wastch of 1 sec. resolution.

SL ARORA-Units and Measurements-Exercise
  1. The respective number of significant figures for the numbers 23.023, 0...

    Text Solution

    |

  2. Resistance of a given wire is obtained by measuring the current flowin...

    Text Solution

    |

  3. The period of oscillation of a simple pendulum is T = 2pisqrt((L)/(g))...

    Text Solution

    |

  4. The currect voltage relation of diode is given by 1=(e^(1000 V//T)-1) ...

    Text Solution

    |

  5. Two full turns of the circular scale of a screw gauge cover a dis...

    Text Solution

    |

  6. A screw gauge gives the following reading when used to mesure the diam...

    Text Solution

    |

  7. A student measured the length of a rod and wrote it as 3.50 cm. Which ...

    Text Solution

    |

  8. In a experiment the angle are required to be measured using an ...

    Text Solution

    |

  9. A spectrometer gives the following reading when used to measure the an...

    Text Solution

    |

  10. A student measures the time period of 100 ocillations of a simple pend...

    Text Solution

    |

  11. The density of a material in the shape of a cube is determined by meas...

    Text Solution

    |

  12. The following observations were taken for dtermining the surface tensi...

    Text Solution

    |

  13. A screw gauge with a pitch of 0.5mm and a circular scale with 50 divis...

    Text Solution

    |

  14. How many Angstrom are there in one metre ?

    Text Solution

    |

  15. One nanometre is equal to

    Text Solution

    |

  16. Light year is the unit of

    Text Solution

    |

  17. Parsec' is the unit of :

    Text Solution

    |

  18. Length cannot be measured by

    Text Solution

    |

  19. The difference in the lengths of a mean solar day and a sidereal day i...

    Text Solution

    |

  20. Gravitational mass is proportional to gravitational

    Text Solution

    |