Two projectiles are thrown with different velocities and at different angles so as to cover the same maximum height. Show that the sum of the times taken by each to reach the highest point is equal to the total time taken by either of the projectiles.

Two projectiles are projected from the same point different velocities and different angles of projection .If the maximum height attained by both the projectiles is same, show that sum of the times taken by each to reach the highest point is equal to the total time of flight of either of the projectiles .

Prove that time taken by a body to rise to highest point is always equal to the time taken by it to fall through he same height.

A projectile is thrown at angle beta with vertical.It reaches a maximum height H .The time taken to reach the hightest point of its path is

Show that there are two values of time for which is projectile is at the same height. Also show that the sum of these two times is equal to the time of flight.

A projectile thrown with velocity v making angle theta with vertical gains maximum height H in the time for which the projectile remains in air, the time period is

If time taken by the projectile to reach Q is T , than PQ =

Two projectiles are fired at different angles with the same magnitude of velocity such that they have the same range. At what angles they might have been projected ?

Two projectile are projected with the same velocity. If one is projected at an angle of 30^(@) to the horizontal. The ratio if maximum heights reached, is:

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?