A 2kg particle starts at the origin and moves along the positive x-axis. The net force acting on it measured at intervals of 1 m : 27.9, 28.3, 30.9, 34.0, 34.5, 46.9, 48.2, 50.0, 63.5, 13.6, 12.2, 32.7, 46.6 and 27.0 (in newtons). What is the total work done on the particle in this interval?

What is the median of the numbers 4.6, 0, 9.3, -4.8, 7.6,2.3,12.7,3.5,8.2,6.1,3.9,5.2?

Only one force is acting on a 2.8 kg particle-like object whose position is given by x= 4.0t-5.0t^(2)+2.0t^(3) , with x in meters and t in seconds. What is the work done by the force from t=0 to t= 6.0 s ?

A particle is subjected to a force F_(x) that varies withes position as shown in figure. Find the work done by the force on the body as it moves (a) from x =10.0 m to x =5.0 m , (b) from x =5.0 m to x =10.0 m , (c ) from x =10. 0 m to x =15.0 m , (d) what is the total work done by the force over the distance x =0 to x =15.0 ? .

The weights of 9 boxes in kgms are as follows: 27.5, 31.2, 28.0, 32.0, 29.8, 30.3, 92.0, 28.7, 31.5 Find the appropriate average weight of the boxes.

In the following series is written in the reverse order, which number will be the fourth to the right of the seventh number from the left? 7,3, 9, 7,0,3, 8, 4,6, 2, 1, 0, 5, 11, 13.

A particle is moving along the x-axis and force acting on it is given by F=F_0sinomega_xN , where omega is a constant. The work done by the force from x=0 to x=2 will be

A particle of mass 3 kg is moving along x - axis and its position at time t is given by equation x=(2t^(2)+5)m . Work done by all the force acting on it in time interval t=0 to t=3s is

The position (x) of a particle of mass 1 kg moving along X-axis at time t is given by (x=1/2 t^(2)) metre. Find the work done by force acting on it in time interval from t=0 to t=3 s .

The position (x) of a particle of mass 2 kg moving along x-axis at time t is given by x=(2t^(3)) metre. Find the work done by force acting on it in time interval t=0 to t=2 is :-