A force F=(15+0.50x) acts on a particle ...

A force F=(15+0.50x) acts on a particle in the X-directation ,where F is in newton and x in metre Find the work done ' by this force during a displacecment from x=0 to x=2.0 m .

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A force F=(15+0.50x) acts on a particle in the X-direction ,where F is in newton and x in metre Find the work done ' by this force during a displacement from x=0 to x=2.0 m .

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in metre. Find the work done by this force during a displacement form 1. 0 m to x = 2.0 m.

A force F=(5+2x) acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from x=0 to x=1m.

A force F=a+b x acts on a particle in the X-direction, where a and b are constants. Find the work done by this force during a displacement from x=0 to x=d/

A force F=a+bx acts on a particle in the x-directioin, where a and b are constants. Find the work done by this force during a displacement form x=0 to x=d .

A force F=a+bx acts on a particle in x-direction, where a and b are constants. Find the work done by this force during the displacement from x_1 to x_2 .

A force F=(a+bx) acts on a particle in x direction where a and b are constants . Find the work done by this force during displacement from x_(1) to x_(2) .

A force F = 0.5x + 10 acts on a particle. Here F is in newton and x is in metre. Calculate the work done by the force during the displacement of the particle from x = 0 to x = 2 metre.

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SL ARORA-Work, Energy and power-EXERCISE

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