The relation between the displacement x and the time t for a body of mass 2 kg moving under the action of a force is geven by `x=t^(3)//3` , where x is in metre and t in second ,Calculate the ork done by the body in first 2 seconds.

The displacement of a partcle is given by x=(t-2)^(2) where x is in metre and t in second. The distance coverred by the particle in first 3 seconds is

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

The position of a Particle of Mass 4 g,acted upon by a constant force is given by x= 4t^(2) +t,where x is in metre and t in second .The work done during the first 2 seconds is

Under the action of a force, a 1 kg body moves, such that its position x as function of time t is given by x=(t^(3))/(2). where x is in meter and t is in second. The work done by the force in fiest 3 second is

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is