Figrue shows the F-x graph. Where F is the force applied x is the distance covered by the body along a straight line path. Given that F is in newton and x in metre, what is the work done?

Figure shows three paths connecting points a and b, A single force F does the indicated work on a particle moving along each path in the indicated direction. On the basis of this information, is force F conservative?

A force F=(10+0.5 x) acts on a particle in the x-direction. What would be the work done by this force during a displacement from x=0 to x=2m (F is in newton and x in metre)

A force F is applied on a lawn move at an angle of 60^(@) with the horizontal. If it moves through a distance x , the work done by the force is

The velocity of a body moving in a straight line is increased by applying a constant force F, for some distance in the direction of the motion. Prove that the increase in the kinetic energy of the body is equal to the work done by the force on the body.

Work done = 1000 J Distance = 10 m Force applied = Work done/Distance therefore F ??

According to Newton s second law of motion F =ma where F is the force required to produce an acceleration a in a body of mass m If a = 0 then F = 0 no external force is required to move a body uniformly along a straight line If a force F acts on a body for t seconds the effect of the force is given by Impulse =F xx t =change in linear momentum of the body Average force exerted by the bat is .

According to Newton s second law of motion F =ma where F is the force required to produce an acceleration a in a body of mass m If a = 0 then F = 0 no external force is required to move a body uniformly along a straight line If a force F acts on a body for t seconds the effect of the force is given by Impulse =F xx t = change in linear momentum of the body The retardation of the ball is .

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres. The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is