A simple pendulum of length `1m` has a wooden bob of mass `1kg`. It is struck by a bullet of mass `10g` moving with a speed of `200m//s`. The bullet gets embedded into the bob. Obtain the height to which the bob rises before swinging back.
Take `g=10m//s^(2)`.

A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10^(-2) kg moving with a speed of 2 xx 10^(2) m s^(-1) . The height to which the bob rises before swinging back is (Take g = 10 m s^(-2) )

The wooden bob of a simple Pendulum of length 1 m is struck by a bullet of mass 10^(-3) kg moving with a speed of 300 m s^(-1) . If the bullet gets embedded into the bob then calculate the height to which the bob will rise before going back to mean position. The mass of bob is 0.8 kg .

A wooden bob of mass 1 kg is suspended from a string of length 1 m . It is struck by a bullet of mass 0.02 kg , moving with a speed of 300 m/s , such that the bullet gets embedded inside it . Calculate the maximum height up to which the bob will rise after the impact .

A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30^(@) . Then (g= 9.8m//s^(2)

A simple pendulum of length 1m has bob of mass 100 g. It is displaced through an angle of 60^@ from the vertcal and then released. The kinetic energy of bob when it passes through the mean position is

A bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g. What is the velocity acquired by the block ?

A piece of wood of mass 0.03 kg is dropped from the top of a building 100 m high. At the same time, a bullet of mass 0.02 kg is fired vertically upward with a velocity of 100 m/s from the ground the bullet gets embedded in the wooded piece after striking. find the height to which the combination rises above the building before it starts falling take g=10m//s^(2)