Calculate the horse power of a man who can chew ice at the rate of `60g min.^(-1)`. Given `J = 4.2 J cal^(-1)` and altent heat of ice `= 80 cal g^(-1), 1hp = 746W`.

Power of a man who can chew 0.3 kg ice in one minute is (in cal/s).

A refrigeratior converts 50 gram of water at 15^(@)C intoice at 0^(@)C in one hour. Calculate the quantity of heat removed per minute. Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of ice =80 cal g^(-1)

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

What is the horse power applied by a person while chewing 100g of ice per minute ? Given J = 4.2 joule per calorie.

If a ball of 80 kg mass hits an ice cube and temperature of ball is 100 .^(@)C , then how much ice converted into water ? (Specific heat of ball is 0.2 cal g^(-1) , Latent heat of ice = 80 cal g^(-1) )

How many grams of ice at -14 .^(@)C are needed to cool 200 gram of water form 25 .^(@)C to 10 .^(@)C ? Take specific heat of ice =0.5 cal g^(-1) .^(@)C^(-1) and latant heat of ice = 80 cal g^(-1) .

1 g of a steam at 100^(@)C melt how much ice at 0^(@)C ? (Length heat of ice = 80 cal//gm and latent heat of steam = 540 cal//gm )

A layer of ice 2 cm thick is formed on a pond. The temperature of air is -20^(@)C . Calculate how long it will take for the thickness of ice to increase by 1mm. Density of ice = 1g cm^(-3) . Latent heat of ice = 80 cal g^(-1) . Conductivity of ice = 0.008 cal s^(-1) cm^(-1) .^(@)C^(-1) .

Find the power of a person who can chew 30g of ice in one minute. Latent heat of ice =80cal//gm , J=4.2 joule // cal.