An energies of 4.9 K.W power is used to pump water from a well 50 m deep. Calculate the quantity of water in kilo which it can pump out in one hour.

A 1-KW motor pumps out water from a well 10m deep. Calculate the quantity of water pumped out per second.

A motor of power 10 kW is used to pump water from a well 20 m deep . Calculate the efficiency of the motor if it pumps 200 kg of water every minute . Take g = 10 m//s^(2)

A pump of power 20 kW is used to jump out the water from a well 12 m deep . Calculate the efficiency of the pump if 5,000 kg of water is pumped out in 1 minute .

(a) What is the power of an engine which can lift 600 kg of coal per minut from a mine 20 m deep ? (b) A 2kW motor pumps out water from a well 10m deep. Calculated the quantity of water pumped out per second.

A suction pump at ground level can draw water from a well whose depth of water level is:

An electric pump of 0.8 hp is used in water supply system in a house. Calculate the amount of current drawn by it , if it is connected to 220 V power supply.

An electric pump is used to pump water to fill a water tank of volume 30m^(3) in 20 minute. The pump is on the ground floor and the tank is one the terrace of the building. The centre of the tank is at 400 m above the ground. How much electric power is consumed by the pump, in filling the tank, if the efficiency of the pump is 50%? (g=10m//s^(2) and density of water =10^(3)kg//m^(3) )

An electric pump is used to pump water to fill a water tank of volume 30 m^(3) is 20 minute. The pump is on the ground floor and the tank is on the terrace of the builiding. The centre of the tank is at 40 m above the ground . How much electric power is consumed by the pump, in filing the tank , if the efficiecy of the pump is 50 ? ( g = 10 m//s^(2) and density of water 10 = ^(3) kg //m^(3) )

What is power ? How do you differentiate killowatt from kilowatt hour ? The Jog Falls in Karnataka state are nearly 20 m high. 2000 tonnes of water falls from it in a minute. Calculate the equivalent power if all this energy can be utilized ? (g = 10 m//s^2)