A particle of mass 1 g moving with a velocity `vecv_1=3hati-2hatj m s^(-1)` experiences a perfectly in elastic collision with another particle of mass 2 g and velocity `vecv_2=4hatj-6 hatk m s^(-1)`. The velocity of the particle is

A particle of mass 1.0 g moving with a velocity vecv_1 = (3hati - 2hatj) m/s experiences a perfectly inelastic collision with another particle of mass 2.0 g and velocity vecv_2 = (4hati - 6hatj) m/s. Find the magnitude of the velocity vector vecv of the coalesced particles.

A particle of mass 1.0g moving with velocity v_1=3.0i-2.0j experiences a perfectly inelastic collision with another particle of mass 2.0g and velocity v_2=4.0j-6.0k . Find the velocity of the formed particle (both the vector v and its modulus), if the components of the vectors v_1 and v_2 are given in the SI units.

A particle of mass m moving with velocity vecV makes a head on elastic collision with another particle of same mass initially at rest. The velocity of the first particle after the collision will be

A 120 g mass has a velocity vecv=2hati+5hatj m s^(-1) at a certain instant. Its kinetic energy is

A particle of mass m moving with velocity u collides elastically head on with a particle of mass 2m at rest. After collision the heavier particle moves with velocity?

Particle A of mass m_1 moving with velocity (sqrt3hati+hatj)ms^(-1) collides with another particle Bof mass m_2 which is at rest initially. Let vec(V_1) and vec(V_2) be the velocities of particles A and B after collision respectively. If m_1 = 2m_2 and after collision vec(V_1) - (hati + sqrt3hatj)ms^(-1) , the angle between vec (V_1) and vec (V_2) is :

A partical of mass m moving with velocity 1m//s collides perfectly elastically with another particle of mass 2m . If the incident particle is deflected by 90^(circ) . The heavy mass will make and angle theta with the initial direction of m equal to:

A particle of mass m moving with a velocity (3hati+2hatj)ms^-1 collides with another body of mass M and finally moves with velocity (-2hati+hatj)ms^-1 . Then during the collision

A particle of mass 15 kg has an initial velocity vecv_(i) = hati - 2 hatjm//s . It collides with another body and the impact time is 0.1s, resulting in a velocity vecc_f = 6 hati + 4hatj + 5 hatk m//s after impact. The average force of impact on the particle is :