A pump on the ground floor of a building can pump of water to fill a tank of volume `30 ms^(3)` in `15 min`. If the tank is `40m` above the ground and the efficiency of the pump is `30 %` , how much electric power is consumed by the pump? `("Take" g = 10 ms^(2))`

A pump on the ground floor of a building can pump of water to fill a tank of voilume 30 ms^(3) in 15 min . If the tank is 40m above the ground and the efficiency of the pump is 30 % , how much elertric power is consumed by the pump? ("Take" g = 10 ms^(2))

An electric pump is used to pump water to fill a water tank of volume 30m^(3) in 20 minute. The pump is on the ground floor and the tank is one the terrace of the building. The centre of the tank is at 400 m above the ground. How much electric power is consumed by the pump, in filling the tank, if the efficiency of the pump is 50%? (g=10m//s^(2) and density of water =10^(3)kg//m^(3) )

An electric pump is used to pump water to fill a water tank of volume 30 m^(3) is 20 minute. The pump is on the ground floor and the tank is on the terrace of the builiding. The centre of the tank is at 40 m above the ground . How much electric power is consumed by the pump, in filing the tank , if the efficiecy of the pump is 50 ? ( g = 10 m//s^(2) and density of water 10 = ^(3) kg //m^(3) )

The power of a motor pump is 5 kW. How much water per minute the pump an raise to height of 20 m ? Take g = 10ms ^-2 .

An engine pumps up 100 kg water through a height of 10 m in 5 s . If effcienecy of the engine is 60% . What is the power of the engine? Take g = 10 ms^(2) .

A tank on the roof of a 20 m high building can hold 10 m^(3) of water. The tank is to be filled form a pond on the ground in 20 minutes. If the pump has an efficiency of 60 % , then the input power in kW is

The power of a motor pump is 2kW. How much water per minute the pump can raise to a heiht of 10 m ? (Given g = 10 m//s^2)

A motor of power 10 kW is used to pump water from a well 20 m deep . Calculate the efficiency of the motor if it pumps 200 kg of water every minute . Take g = 10 m//s^(2)