A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions. The total energy released in the process of explosion is ............

A particle of mass 4 m which is at rest explodes into masses m, m & 2m . Two of the fragments of masses m and 2m are found to move with equal speeds v each in opposite directions. The total mechanical energy released in the process of explosion is :-

A body of mass 4m at rest explodes into three pieces. Two of the pieces each of mass m move with a speed v each in mutually perpendicular directions. The total kinetic energy released is

A body of mass 5m initially at rest explodes into 3 fragments with mass ratio 3:1:1. Two of fragments each of mass 'm' are found to move with a speed 60m//s in mutually perpendicular direction. The velocity of third fragment is

A particle of mass 5 m at rest suddenly breaks on its own into three fragments . Two fragments of mass m of each move along mutully perpendicular direction with speed v each . The energy released suring the process is

A particle of mass 4m which is at rest explodes into four equal fragments. All four fragments scattered in the same horizontal plane. Three fragments are found to move with velocity v as shown in the figure. The total energy released in the process is

A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragments are scattered in the same horizontal plane. Three fragments are found to move with velocity V each as shown in the figure. The total energy released in the process of explosion is

A body kept at rest explodes in four identical fragments and it is found that three of them move along mutually perpendicular directions with same kinetic energy K . Total energy released in the explosion is

There is an object of mass 5m kept at rest in space. Suddenly it explodes in three parts of masses m , 2m and 2m . Two parts of equal masses are found to move with equal speeds v along perpendicular directions . If energy released in explosion is nmv^(2) , then find value of n .